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Georgia [21]
3 years ago
8

Give the coordinates of the point obtained from each reflection.

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0
If it’s reflected on the x-axis than change the y-axis to its opposite. And if it’s reflected on the y-axis than change the x-axis to its opposite. Hope this helps
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Is this correct? im not sure about the second ques

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3 years ago
Hey help me with this no trolls
german

Answer:

Peytons car travels 14.8 miles less than Madeline's car in with one gallon

Step-by-step explanation:

peytons car uses 1 gal to travel 22.1 miles and Madeline's care uses 1 gal to travel 36.9. 36.9-22.1 = 14.8

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6 0
3 years ago
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AleksandrR [38]

Answer:

g(x) is greater

Step-by-step explanation:

it is greater because when mulitplying the function g and x you get a higher number than you would with f(x)

hope that helps!!

5 0
3 years ago
A rectangular vegetable patch has a perimeter of 28 meters and an area of 48 square
aliina [53]

Answer:

Length = 8 meters

Width = 6 meters

Step-by-step explanation:

Given the following information:

Perimeter of a rectangular vegetable patch: 2(L + W) = 28 meters

Area = L × W = 48 m²

We can solve for the dimensions by using both equations.

First, let's use the formula for the perimeter of the rectangular vegetable patch, and isolate one of the given variables:

2(L + W) = 28

Divide both sides by 2:

\frac{2(L + W)}{2} = \frac{28}{2}

L + W = 14

Subtract W from both sides to isolate L:

L + W - W = 14 - W

L = 14 - W

Next, we'll take the formula for the area, and substitute the value for the L from our previous step:

A = 48  =  L × W

48  = W × (14 - W)

Distribute W into the parenthesis:

48 = 14W - W²

Add W² and subtract 14W to both sides:

W² - 14W + 48 = 14W - 14W - W² + W²

W² - 14W + 48 = 0   ⇒ This represents a quadratic equation in standard form. We can use the coefficient and constant values to solve for its roots.

a = 1, b = -14, and c = 48

Substitute these values into the quadratic equation:

x = \frac{-b +/- \sqrt{b^{2}-4ac}}{2a}

x = \frac{14 +/- \sqrt{(-14)^{2}-4(1)(48)}}{2(1)}

x = \frac{14 +/- \sqrt{196-192}}{2}

x = \frac{14 +/- \sqrt{4}}{2}

x = \frac{14 + 2}{2}, x = \frac{14 - 2}{2}

x = 8, x = 6

Now, we can substitute these values into the formulas for the perimeter and area to find the true dimensions of the rectangular vegetable patch.

Perimeter: 2(L + W) = 2(8 + 6) = 28 meters

Area = L × W = 8 × 6  = 48 m²

Therefore, the dimensions of the rectangular vegetable patch are:

Length = 8 meters

Width = 6 meters

Dimensions: 8 × 6 meters.

3 0
3 years ago
Bobbie wants to make $2.00 using dollars half dollars and quarters.how many different ways can she make $2.00?
Solnce55 [7]

Answer:

8 * 1/4

6 * 1/4 + 1/2

4 * 1/4 + 2 * 1/2

2 * 1/4 + 3 * 1/2

4 * 1/2

4 * 1/4 + 1 * 1

2 * 1/4 + 1/2 + 1 * 1

2 * 1/2 + 1 * 1

2 * 1

There are 9 different ways.

5 0
4 years ago
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