Answer:
x = 5
, y = 3
Step-by-step explanation:
Solve the following system:
{3 x + 4 y = 27 | (equation 1)
5 x - 3 y = 16 | (equation 2)
Swap equation 1 with equation 2:
{5 x - 3 y = 16 | (equation 1)
3 x + 4 y = 27 | (equation 2)
Subtract 3/5 × (equation 1) from equation 2:
{5 x - 3 y = 16 | (equation 1)
0 x+(29 y)/5 = 87/5 | (equation 2)
Multiply equation 2 by 5/29:
{5 x - 3 y = 16 | (equation 1)
0 x+y = 3 | (equation 2)
Add 3 × (equation 2) to equation 1:
{5 x+0 y = 25 | (equation 1)
0 x+y = 3 | (equation 2)
Divide equation 1 by 5:
{x+0 y = 5 | (equation 1)
0 x+y = 3 | (equation 2)
Collect results:
Answer: {x = 5
, y = 3
Step-by-step explanation:
log2x = 1 - log(x+4)
log2x = log10 - log(x+4)
log2x = log[10/(x+4)]
2x = 10/(x+4)
2x(x+4) = 10
2x² + 8x - 10 = 0
÷2 both sides of equation
x² + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5, 1
x isn't be -5 because logA, A need to be > 0
So, x value is 1
Answer:
D
Step-by-step explanation:
i had the same answer and got it right
Real numbers, rational numbers, Integers, Whole numbers, and Natural numbers.
