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kykrilka [37]
3 years ago
10

Mr. Jenkins is buying paint to paint the garage wall. He needs to know the area of the wall in order to know how much paint he w

ill need to buy. The wall is 24 feet wide and 12 feet tall. What is the area of the garage wall?
Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0

Answer:

288

Step-by-step explanation:

just  multiply its height by its width let me know if im wrong or not please

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A horseback riding trail is 1 mi 40.8 ft long. How long is the trail in yards, feet, and inches?
ch4aika [34]

Answer:  1773.6 yards   5320.8 feet  64324.8 inches

Step-by-step explanation:  

1 mile in yards = 1760                                                                                         40.8 feet in yards = 13.6      1760 + 13.6 =<u> 1773.6 yards </u>

1 mile in feet = 5280 + 40.8 = <u> 5320.8 feet </u>

1 mile in inches  = 63360

40.8 feet in inches = 964.8

63360 + 964.8 = <u>64324.8 inches </u>

<u>hope this helps :) </u>



6 0
4 years ago
The center circle on a playing field has a radius of 7.5m find its circumference
Nady [450]
<h3>Given:</h3>
  • r= 7.5 m
<h3>Note that:</h3>
  • r= radius
<h3>To find:</h3>

The circumference of the circular playing field.

<h3>Solution:</h3>

\huge\boxed{Formula:C= 2\pi{r}}

We'll have to multiply 2, π and radius.

Substitute the values according to the formula.

C= 2× \pi ×7.5

C= 47.12389

\large\boxed{C= 47.12 \: m}

<u>Therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>circumference</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>circular</u><u> </u><u>playing</u><u> </u><u>field</u><u> </u><u>is</u><u> </u><u>47.12</u><u> </u><u>feets</u><u>.</u>

3 0
2 years ago
1092 flowers are arranged into 26 vases with the same number of flowers in each vase. How many flowers would be needed to fill 1
torisob [31]

Answer:

5460

Step-by-step explanation:

8 0
3 years ago
If y=6 when x=2/3 find x when y=12
motikmotik
Y=6 x=2/3
y=12 x=?
6*2=12, 2/3*2=?
?=2*2/3
?=1 and 1/3
7 0
3 years ago
Read 2 more answers
Please help! And explain.
wariber [46]
\bf \textit{area of a sector of a circle}\\\\&#10;A=\cfrac{\theta r^2}{2}\qquad &#10;\begin{cases}&#10;\theta=\textit{angle in radians}\\&#10;r=radius\\&#10;----------\\&#10;r=5\\&#10;\theta=\frac{\pi }{4}&#10;\end{cases}\implies A=\cfrac{\frac{\pi }{4}\cdot 5^2}{2}\\\\&#10;-----------------------------\\\\&#10;A=\cfrac{\frac{\pi }{4}\cdot 25}{2}\implies A=\cfrac{\frac{25\pi }{4}}{2}\implies A=\cfrac{\frac{25\pi }{4}}{\frac{2}{1}}\implies A=\cfrac{25\pi }{4}\cdot \cfrac{1}{2}&#10;\\\\\\&#10;\boxed{A=\cfrac{25\pi }{8}}
4 0
4 years ago
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