Theo can run 1/2 mile in 1/10 hour. If theo continues at this rate how far can he run in a hour?

BRAINLIEST

IrinaVladis [17]

Answer:

We know that a negative value is positive of all even exponents and negative for all odd exponents.

y=(-1)^x

5 0

3 years ago

In the figure below, the segments overline RS and overline RT are tangent to the circle centered at Given that OS = 3.6 and RT =

ExtremeBDS [4]

Answer:

RS = 4.8

OT = 3.6

From the Pythagorean Theorem we know:

OR^2 = ST^2 + OT^2

OR^2 = 4.8^2 + 3.6^2

OR ^2 = 23.04 + 12.96

OR^2 = 36

OR = 6

Step-by-step explanation:

8 0

3 years ago

Find two supplementary angles if the measure of one angle is three times the measure of the second

Colt1911 [192]

Hello :
x+3x=180
4x=80
x=180/4
x=45°

8 0

3 years ago

A boat can travel at an average speed of 10 miles per hour in still water. Traveling with the current, it can travel 6 miles in

oksano4ka [1.4K]

Answer: The speed of the current is 2 miles per hour.

Step-by-step explanation:

We know that the speed of the boat is:

S = 10 mph.

When the boat travels with the current, the speed will be:

S = 10mph + x

where x = speed of the current.

When the boat travels against the current, the speed will be:

S = 10mph - x

Now, for a given amount of time T, when the boat travels with the current, it moves a distance of 6 miles.

Then we have the equation:

(10mph + x)*T = 6mi

And against the current, in the same time the boat moves 4 mi, then:

(10 mph - x)*T = 4mi

Then we have the system of equations:

(10mph + x)*T = 6mi

(10 mph - x)*T = 4mi

Now, we can take the quotient of these two equations and get:

((10mph + x)*T)/((10 mph - x)*T) = (6mi/4mi)

(10mph + x)/(10 mph - x) = 3/2

Now we can solve this for x.

(10mph + x) = (3/2)*(10 mph - x)

10mph + x = (3/2)*10mph - (3/2)*x

x + (3/2)*x = (3/2)*10mph - 10mph

(5/2)*x = (1/2)*10mph = 5mph

x = (2/5)*5mph = 2mph.

The speed of the current is 2 miles per hour.

6 0

3 years ago

Read 2 more answers

Find the lateral area for the pyramid with the equilateral base

likoan [24]

<h3>The lateral area for the pyramid with the equilateral base is 144 square units</h3>

Solution:

The given pyramid has 3 lateral triangular side

The figure is attached below

Base of triangle = 12 unit

Find the perpendicular

By Pythagoras theorem

$hypotenuse^2 = opposite^2 + adjacent^2$

Therefore,

$opposite^2 = 10^2 - 6^2\\\\opposite^2 = 100 - 36\\\\opposite^2 = 64\\\\opposite = 8$

Find the lateral surface area of 1 triangle

$\text{ Area of 1 lateral triangle } = \frac{1}{2} \times opposite \times base$

$\text{ Area of 1 lateral triangle } = \frac{1}{2} \times 8 \times 12\\\\\text{ Area of 1 lateral triangle } = 48$

Thus, lateral surface area of 3 triangle is:

3 x 48 = 144

Thus lateral area for the pyramid with the equilateral base is 144 square units

5 0

3 years ago