So a times 10^n where 1≤|a|<10 and n is an integer is what i learned

so

a.
234=
2.34 times 100=
2.34 times 10²

b.
0.000052=
5.2 times 1/100000=
5.2 times 10⁻⁵

c.
-220000=
-2.2 times 100000=
-2.2 times 10⁵

d. ok, so just count the spaces moved to the left
-18.2 times 10⁻¹⁵

6 0

3 years ago

What is the solution for -10 < x - 9?

algol13

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-10 < x - 9

Add 9 to both sides:

-1 < x

The correct answer would be option C

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- Ally ✧

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7 0

3 years ago

A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As

Semenov [28]

Answer:

$0.2564\text{ pounds}$

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the $X$ percentile for the television weights, use the formula:

$X=\mu +k\sigma$ , where $\mu$ is the average of the set, $k$ is some constant relevant to the percentile you're finding, and $\sigma$ is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute $\mu=5$ , $k=1.282$ , and $\sigma=0.1$ :