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docker41 [41]
3 years ago
13

A zip line starts on a platform that is 40 meters above the ground. The anchor for the zip line is 198 horizontal meters from th

e base of the platform. How long is the zip line? help grifjin
Mathematics
1 answer:
Damm [24]3 years ago
7 0

Answer:

Solution given:

perpendicular distance =height [p]=40m

base or horizontal distance [b]=198m

Hypotenuse or zip line [h]=?

Now

By using Pythagoras law

h²=p²+b²

h²=40²+198²

h=√40804

h=202m

<u>So</u><u> </u><u>the</u><u> </u><u>Zip</u><u> </u><u>line</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u>2</u><u>m</u><u> </u><u>long</u><u>.</u>

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For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les
kaheart [24]

Answer:

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The margin of error for this case is given by:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259

And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation  

n=1000 represent the random sample taken    

\hat p=0.52 estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

\alpha=0.05 represent the significance level (no given, but is assumed)    

Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The margin of error for this case is given by:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259

And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

5 0
3 years ago
A negative number raised to an odd power is _____ negative.
BartSMP [9]
Answer – Always
 A negative number raised to an odd power is always negative. When a negative number is raised to an even power, the pairs of negatives will cancel out; but when it is raised to an odd power, after pairs of the negative sign have canceled each other out, there will still be one minus sign left unpaired, which will not cancel out. <span>
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4 0
3 years ago
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Answer:

The percent of error in her measurement is 1.3%

Step-by-step explanation:

we know that

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C=\pi D

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D is the diameter

we have

D=5\ in

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substitute

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Answer:

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Step-by-step explanation:

4 quarters is 1 dollar

1 nickel is 5 cent

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3 years ago
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Answer:

Step-by-step explanation:

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2 years ago
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