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sergiy2304 [10]
3 years ago
10

Find the 9th term of the geometric sequence 10, 40, 160, ANSWER ASAP 50 points

Mathematics
1 answer:
Anna007 [38]3 years ago
8 0

Step-by-step explanation:

U _{ {9}^{th} } \: term = U  _{ {1}^{st} } {r}^{(n - 1)}  \\  = 10 \times  {4}^{(9 - 1)}  \\  = 655360 \\  {9}^{th}  \: term \: is \: 655360

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Assume a_k. Now when n=k+1, you have

a_{k+1}=\dfrac{3^{k+1}}{(2k+2)!}=\dfrac3{(2k+2)(2k+1)}\times\dfrac{3^k}{(2k)!}=\dfrac3{(2k+2)(2k+1)}a_k

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