1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Reika [66]
3 years ago
7

A flying squirrel lives in a nest that is 6 meters up in a tree but wants to eat an acorn that is on the ground 4 meters away fr

om the base of his tree if the flying squirrel glides from his nest to the acorn the scurries back to the base of the tree and then climbs back up the tree to his nest how far will the flying squirrel travel in total?
Mathematics
1 answer:
KiRa [710]3 years ago
3 0
4 jus think about it
You might be interested in
9.
alex41 [277]

Answer:  B. c = 16d + 18

I'm gonna go with c = 16d + 18

Step-by-step explanation:  letter B or letter D

Answer

5.0/5

6

Brainly User

Days : 1    2    3    4 →→→→→→D(X axis)

Rent a Truck:  34   50  66    82→→→→→→R(Y axis)

As  you can observe from number of Days and Amount to rent a truck , if you rent for a day the price being $ 34 and with increase in Day the rent increases by $ 16.

Plotting the point on graph , found that these points are collinear.

So, we can Represent this relation between days and Rent in equation of two variables representing a line.

Two point formula of line:

 →→Equation of line passing through two points  

So , line representing Days and rent is :

So, the rule representing Days and Rent is:  16 D - R + 18=0

...............................................................................................................................................

The answer is 18

If you subtract 47-29=18

Then if you subtract 47-65=18 the pattern is to add 18

7 0
2 years ago
Find x.______________a0
velikii [3]

Answer:

x=4

Step-by-step explanation:

Before we find x, we need to set up this triangle a little more. We need to find the triangle's altitude before we can solve for x. We will use the heartbeat method to find the altitude.

Let altitude = y; solve for y:

\frac{2}{y}=\frac{y}{6}

y^2=12

y=\sqrt{12}

y=2\sqrt{3}

Now that we know the altitude, we can use the Pythagorean Theorem to find the hypotenuse (x).

a^2+b^2=c^2

2^2+(2\sqrt{3})^2=c^2

4+12=c^2

c^2=16

c=4

Since c and x are the same; c is just the hypotenuse in the Pythagorean Theorem.

x=4

4 0
3 years ago
The nearest ten 1202(38)
Advocard [28]

Answer:

1202 is rounded to 1200

38 is rounded to 40

1200(40)= 48,000

7 0
3 years ago
The probability of rolling a 5 on a six-sided number cube is 1/6. What is the probability of not rolling a 5 on a six-
Nezavi [6.7K]

Answer:

Step-by-step explanation:

Event of not rolling a 5= {1,2,3,4,6}

P(not rolling a 5) = 5/6

5 0
2 years ago
How tall is the flag pole?​
maxonik [38]

Answer:

17

Step-by-step explanation:

6 0
3 years ago
Other questions:
  • Sarahs investment in stock grew 16% to $522.How much did she invest.
    15·1 answer
  • Three times the sum of half a number and 7 is 36
    9·1 answer
  • A student bought a juice pouch for $2.50 and 3 bags of chips . The total cost was $5.05 write and solve an equation to determine
    13·2 answers
  • Solve for Z. No fractions or variables in solution.
    14·1 answer
  • If you use 25,26,27 witch number should you choose if you want to move spaces as possible? explain
    9·1 answer
  • Which of the following determines a plane?
    13·1 answer
  • Solve for x: <br><br>(x+3)²=1​
    14·1 answer
  • Roger and his sister started watching a cartoon movie at 2:45 P.M. The movie was 2 hours and 15 minutes long. After the movie, t
    9·1 answer
  • HELPPP Paul is making two ceramic plates in his pottery class. One plate has a 20-centimeter diameter and a 62.8-centimeter circ
    6·1 answer
  • Eva is working two summer jobs, making $16 per hour tutoring and $8 per hour clearing tables. Last week Eva worked 3 times as ma
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!