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3 years ago

The braking distance Dv (in meters) for a certain car moving at velocity v (in meters/second) is given by =Dvv234.

Mathematics

1 answer:

MaRussiya [10]3 years ago

8 0

Answer:

S(t)= $\frac{9t^2}{34}$

Step-by-step explanation:

We are given that

Th braking distance for a certain car moving at velocity v(in m/s) is given by

$D(v)=\frac{v^2}{34}$

The velocity of car B(t) t seconds after starting = $B(t)=3t$

We have to find the value for braking distance S(t) after t seconds.

To find the formula for braking distance we will substitute the value of velocity B(t) in place of v in D(v)

Substitute the value of velocity then we get

Then, we get

The formula for the braking distance S(t) after t seconds= $\frac{(3t)^2}{34}$

The formula for the braking distance S(t) after t seconds= $\frac{9t^2}{34}$

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3 years ago

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Answer:

No, there is not enough evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

We are given that a publisher reports that 34% of their readers own a particular make of car. A random sample of 220 found that 30% of the readers owned a particular make of car.

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Null Hypothesis, $H_0$ : p = 0.34 {means that the percentage of readers who own a particular make of car is same as reported 34%}

Alternate Hypothesis, $H_1$ : p $\neq$ 0.34 {means that the percentage of readers who own a particular make of car is different from the reported 34%}

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Therefore, we conclude that the actual percentage of readers who own a particular make of car is same as reported percentage and the executive's claim that it is different is not supported.

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