Question

The braking distance Dv (in meters) for a certain car moving at velocity v (in meters/second) is given by =Dvv234.

Answer 1

Answer:

S(t)=$\frac{9t^2}{34}$

Step-by-step explanation:

We are given that

Th braking distance for a certain car moving at velocity v(in m/s) is given by

$D(v)=\frac{v^2}{34}$

The velocity of car B(t) t seconds after starting =$B(t)=3t$

We have to find the value for braking distance S(t) after t seconds.

To find the formula for braking distance we will substitute the value of velocity B(t) in place of v in D(v)

Substitute the value of velocity then we get

Then, we get

The formula for the braking distance S(t) after t seconds=$\frac{(3t)^2}{34}$

The formula for the braking distance S(t) after t seconds=$\frac{9t^2}{34}$