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PSYCHO15rus [73]
3 years ago
15

Pythagorean theorem a=7 and c=14. Can you explain how to find b?​

Mathematics
1 answer:
nikdorinn [45]3 years ago
8 0

Answer:

c squared - a squared = b squared

Step-by-step explanation:

Since a squared + b squared = c squared

With these values it would equal 14 squared - 7 squared = c squared

Then after you find c squared, find the square root of it and there you have go your answer!

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HALP ME PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
Ne4ueva [31]

Answer:

x = -\frac{1}{3}, y = 2

Step-by-step explanation:

3x + 3y - 7 = 12x + y

6y - 12x - 1 = -45x

(3x - 12x) + (3y - y) = 7

(-12x + 45x) + 6y = 1

-3(-9x + 2y = 7)

33x + 6y = 1

27x - 6y = -21

33x + 6y = 1

60x = -20 -> x = -20/60 = -1/3

-9x + 2y = 7 -> y = \frac{7+9x}{2} = \frac{7+9*-\frac{1}{3}}{2} = 2

4 0
3 years ago
Solve for<br> 8 - 6r + 3 = 5
Oksanka [162]

Answer:

r = 1

Step-by-step explanation:

8 - 6r + 3 = 5

Combine like terms

11 - 6r = 5

Subtract 5 from both sides

6 - 6r = 0

Add 6r to both sides

6 = 6r

Divide both sides by 6

1 = r

5 0
3 years ago
If (3, y) lies on the graph of y = -(2^x) then y=<br> 1/8<br> -6<br> -8
vazorg [7]
<h3>Answer is   -8</h3>

Work Shown:

y = -(2^x)

y = -(2^3) ... replace x with 3

y = -(2*2*2) ... expand out 2 cubed

y = -8

8 0
3 years ago
Read 2 more answers
Which quantity is proportional to 35⁄80?<br> Check all that are true.
elena-14-01-66 [18.8K]
What are the options
4 0
3 years ago
How would you use the Fundamental Theorem of Calculus to determine the value(s) of b if the area under the graph g(x)=4x between
-BARSIC- [3]
The Fundamental Theorem of Calculus regarding geometry states that 
\int\limits^b_a g{(x)} \, dx = F(b)-F(a)

Where F is the indefinite integral of g(x)

The first step is to integrate g(x)
\int\ {4x} \, dx = \frac{4x^{1+1} }{1+1} = \frac{4x^{2} }{2} =2 x^{2}

Then substitute the value of b and a=1 into 2x^{2}

[2 (b)^{2}]-[2 (1)^{2}] = 240
2b^{2} -2=240
2b^{2}=240+2
2b^{2}=242
b^{2}= \frac{242}{2}
b^{2}=121
b=11

Hence the limit of the area under g(x) is between a=1 and b=11

6 0
3 years ago
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