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Molodets [167]
2 years ago
6

The stopping distance, D, in feet of a car is directly proportional to the square of it's speed, V. Write the direct variation e

quation for the scenario above.
Mathematics
1 answer:
kow [346]2 years ago
4 0

Answer:

D=kV^2

Step-by-step explanation:

In this problem, it is given that,

The stopping distance, D, in feet of a car is directly proportional to the square of it's speed, V.

We need to write the direct variation equation for the scenario above. It can be given by :

D\propto V^2

To remove the constant of proportionality, we put k.

D=kV^2

k is any constant

Hence, this is the required solution.

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\dfrac{21}{32}\cdot\dfrac{39}{120}\cdot\dfrac{40}{65}=\dfrac{21}{32}\cdot\dfrac{3\cdot13}{2\cdot2\cdot2\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot2\cdot5}{5\cdot13}=\\\\\\=\dfrac{3\cdot7}{32}\cdot\dfrac{13}{2\cdot2\cdot2\cdot5}\cdot\dfrac{2\cdot2\cdot2}{13}=\dfrac{21}{32}\cdot\dfrac{1}{5}\cdot\dfrac{1}{1}=\dfrac{21}{160}

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