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3 years ago

neptune is 4,498,252,900 kilometers from the sun. Which distance is 200,000,000 kilometers closer to the sun?

2 answers:

8 0

I think it would be 4,478,252,900. I think you would have to subtract 200,000,000 from 4,498,252,900 and that would be your answer ^

Virty [35]3 years ago

3 0

The average distance of Neptune from the Sun is 2,795,084,800 miles or 4,498,252,900 kilometers. Because its orbit is elliptical, its distance from the Sun changes depending on where it is in its orbit. The closest Neptune gets to the Sun is 2,771,087,000 miles or 4,459,630,000 kilometers. The farthest it gets from the Sun is 2,819,080,000 miles or 4,536,870,000 kilometers.

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What is the solution for 10+2w>=22 or 5w-8>-12

Marina CMI [18]

Answer:

no solution

Step-by-step explanation:

10+2w>=22 or 5w-8>-12

10-2w>=22 or (5w-2w)-8>-12

10>=22 or 3w+8>12

18>=22 or 3w>12

18/3>=22 or 3w/3>12

6>=22 or w>12

3 0

2 years ago

What scale factor was applied to the first rectangle to get the resulting image?

yulyashka [42]

You would take 3 into 7.5 to get that scale factor.

7 0

3 years ago

Let f(x) = 3x + 2 and g(x) = x - 3. Find g(x) - f(x) and state its domain.

Bad White [126]

We have that

f(x) = 3x + 2
g(x) = x - 3

[g(x) - f(x)]=(x-3)-(3x+2)--------> (x-3-3x-2)-----> -2x-5

the domain is all real numbers

the answer is
–2x – 5; all real numbers

3 0

3 years ago

Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250$

Step-by-step explanation:

Given:

$T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}$

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

$T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}$

now we need to solve this integral!

$T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}$

$T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0$

$T = \left|-1250e^{-0.04t}\right|^{\infty}_0$

$T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})$

when any number has a power of negative infinity it is 0. because: $a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0$ , like something being divided by a very large number!

$T = (-1250(0))-(-1250e^0)$

$T = 1250$

this is the total amount of waste

6 0

3 years ago

Hannah buys (2 1/5) dried fruit for 1.50 how much will she pay for 1 pound?

Vlada [557]

1.5x1/5=.3
half of 1.5 (because of 2 lbs of dried fruit ) is .75
.75+.3=.78 cents for 1 lb

8 0

4 years ago