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tangare [24]
4 years ago
11

Ayudenme porfa doy corona xd

Chemistry
1 answer:
vova2212 [387]4 years ago
5 0

Answer:

e) 5

Explanation:

Because it's H

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Fe2O3(s) + 3CO(
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6 0
4 years ago
Identify the charge carried by a phosphide ion
insens350 [35]

Answer : The charge carried by a phosphide ion is, (-3)

Explanation :

In phosphide ion, the (-ide) indicates that the phosphide ion is the anion of phosphorous. So, we will have to add electrons.

As we know that the phosphorous belongs to group 5 and have 5 valence electrons.

The atomic number of phosphorous = 15

The electronic configuration of phosphorous is, 1s^22s^22p^63s^23p^3

In phosphorous, the 'p' sub-shell is half filled. For fully filled 'p' sub-shell, we will need '3' electrons. By adding 3 electrons in 'p' sub-shell of phosphorous, (-3) charge will be created on phosphorous and named as phosphide ion.

Phosphide ion is written as, P^{3-}

5 0
3 years ago
There are two valence electrons in a He atom. What is the average ionization energy of the two valence electrons in He
motikmotik

Answer:

A: Calcium is a group 2 element with two valence electrons. Therefore, it is very reactive and gives up electrons in chemical reactions. It is likely to react with an element with six valence electrons that “wants” to gain two electrons. This would be an element in group 6, such as oxygen.

3 0
3 years ago
Be sure to answer all parts. Calculate the pH of the following two buffer solutions: (a) 1.4 M CH3COONa/1.6 M CH3COOH. (b) 0.1 M
aalyn [17]

Answer:

a) pH = 4.68 (more effective)

b) pH =4.44.

Explanation:

The pH of buffer solution is obtained by Henderson Hassalbalch's equation.

The equation is:

pH =pKa +log\frac{[salt]}{[acid]}

a) pKa of acetic acid = 4.74

[salt] = [CH₃COONa] = 1.4 M

[acid] = [CH₃COOH] = 1.6 M

pH = 4.74 + log \frac{1.4}{1.6}= 4.68

This is more effective as there is very less difference in the concentration of salt and acid.

b) pKa of acetic acid = 4.74

[salt] = [CH₃COONa] = 0.1 M

[acid] = [CH₃COOH] = 0.2 M

pH = 4.74 + log \frac{0.1}{0.2}= 4.44

3 0
4 years ago
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