At room temperature, it is a solid state of matter. hope this helps, have an amazing day :)
The answer is, 699g
The idea here is that you need to use the mole ratio<span> tha exists between </span>ferric oxide<span>, </span><span><span>Fe2</span><span>O3</span></span><span>, and iron metal, </span>Fe<span>, to determine how many moles of the latter will be produced when </span>all the given mass<span> of the ferric oxide reacts...
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Answer : The charge carried by a phosphide ion is, (-3)
Explanation :
In phosphide ion, the (-ide) indicates that the phosphide ion is the anion of phosphorous. So, we will have to add electrons.
As we know that the phosphorous belongs to group 5 and have 5 valence electrons.
The atomic number of phosphorous = 15
The electronic configuration of phosphorous is, 
In phosphorous, the 'p' sub-shell is half filled. For fully filled 'p' sub-shell, we will need '3' electrons. By adding 3 electrons in 'p' sub-shell of phosphorous, (-3) charge will be created on phosphorous and named as phosphide ion.
Phosphide ion is written as, 
Answer:
A: Calcium is a group 2 element with two valence electrons. Therefore, it is very reactive and gives up electrons in chemical reactions. It is likely to react with an element with six valence electrons that “wants” to gain two electrons. This would be an element in group 6, such as oxygen.
Answer:
a) pH = 4.68 (more effective)
b) pH =4.44.
Explanation:
The pH of buffer solution is obtained by Henderson Hassalbalch's equation.
The equation is:
![pH =pKa +log\frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pH%20%3DpKa%20%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
a) pKa of acetic acid = 4.74
[salt] = [CH₃COONa] = 1.4 M
[acid] = [CH₃COOH] = 1.6 M

This is more effective as there is very less difference in the concentration of salt and acid.
b) pKa of acetic acid = 4.74
[salt] = [CH₃COONa] = 0.1 M
[acid] = [CH₃COOH] = 0.2 M
