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vodomira [7]
3 years ago
10

State the reason that soft drinks is a mixture and water is a compound?

Chemistry
2 answers:
Yuri [45]3 years ago
7 0
Carbonated drinks are a mixture of many compounds such as glucose(sugar) and others, while water is simply its own molecule.
Softa [21]3 years ago
3 0
Soft drinks can be separated hydrogen and oxygen (water) can't be separated
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Which best describes a neutralization reaction?
Softa [21]
A reaction between to acids
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What is the smallest division on this balance?
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0.001 would be the smallest.

Good Luck! :)
4 0
4 years ago
Read 2 more answers
A reaction was suppose to produce 20 L of gas. Only 12 litters of gas were produced in the lab. What is the percent yield for th
pogonyaev

Answer:

\boxed {\boxed {\sf 60 \%}}

Explanation:

Percent yield is a ratio of the actual yield to the theoretical yield. It is found using this formula:

\% \ yield= \frac {actual \ yield}{theoretical \  yield} *100

The actual yield is 12 liters, because that was actually produced in the lab.

The theoretical yield is 20 liters, because that was the expected yield.

\% \ yield= \frac {12 \ L}{20\ L} *100

\% \ yield= 0.6*100

\% \ yield= 60

For this reaction, the percent yield is 60%.

5 0
3 years ago
What is a Spontaneous charge
ddd [48]

This means a release of free energy from the system corresponds to a negative change in free energy, but to a positive change for the surroundings.

3 0
3 years ago
fills a 500.mL flask with 3.6atm of carbon monoxide gas and 1.2atm of water vapor. When the mixture has come to equilibrium she
enot [183]

Answer:

The answer to the question is

The pressure of carbon dioxide after equilibrium is reached the second time is 0.27 atm rounded to 2 significant digits

Explanation:

To solve the question, we note that the mole ratio of the constituent is proportional to their partial pressure

At the first trial the mixture contains

3.6 atm CO

1.2 atm H₂O (g)

Total pressure = 3.6+1.2= 4.8 atm

which gives

3.36 atm CO

0.96 atm H₂O (g)

0.24 atm H₂ (g)

That is

CO+H₂O→CO(g)+H₂ (g)

therefore the mixture contained

0.24 atm CO₂ and the total pressure =

3.36+0.96+0.24+0.24 = 4.8 atm

when an extra 1.8 atm of CO is added we get Increase in the mole fraction of CO we have one mole of CO produces one mole of H₂

At equilibrium we have 0.24*0.24/(3.36*0.96) = 0.017857

adding 1.8 atm CO gives 4.46 atm hence we have

 (0.24+x)(0.24+x)/(4.46-x)(0.96-x) = 0.017857

which gives x = 0.031 atm or x = -0.6183 atm

Dealing with only the positive values we have the pressure of carbon dioxide = 0.24+0.03 = 0.27 atm

7 0
3 years ago
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