Question 13

A company makes wax candles in the shape of a cylinder. Each candle has a diameter of 8 inches and a height of 3 inches. How muc

Sveta_85 [38]

Answer:

18,086.4 cubic units

Step-by-step explanation:

The volume of one such cylinder can be computed by multiplying the height by pi by the radius squared: 3×3.14×4²=150.72.

If you want to make 120 candles, multiply that number by 120: 150.72×120=18086.4.

3 0

3 years ago

How many faces does this shape have?

Veseljchak [2.6K]

DO NOT LISTEN TO THE OTHER PERSON, you can CLEARLY see thats not the right answer. She/He is bluffing.

The true answer:
The shape has 4 faces. Faces means the sides of a 3d figure/the sides are the 2d shapes that form together to form one 3d figure. Btw that figure is a triangular pyramid.
Com.ment me if u have any questions

Have a nice day!

4 0

2 years ago

Find the volume of a right circular cone that has a height of 5.6 m and a base with a radius of 16.6 m. Round your answer to the

marta [7]

Answer:

1615.97 m^3

Step-by-step explanation:

V=πr^2 h/3

V= π (16.6)^2 (5.6/3)

V= 1615.97 m^3

3 0

3 years ago

Read 2 more answers

What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9

skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let $u^2=x^4\\u = x^2$

Subbing in:

$9u^2-2u-7=0$

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63. We need 2 factors of 63 that will add to give us -2. The factors of 63 are {1, 63}, (3, 21}, {7, 9}. It looks like the combination of -9 and +7 will work because -9 + 7 = -2. Plug in accordingly:

$9u^2-9u+7u-7=0$

Group together in groups of 2:

$(9u^2-9u)+(7u-7)=0$

Now factor out what's common within each set of parenthesis:

$9u(u-1)+7(u-1)=0$

We know this combination "works" because the terms inside the parenthesis are identical. We can now factor those out and what's left goes together in another set of parenthesis:

$(u-1)(9u+7)=0$

Remember that $u=x^2$

so we sub back in and continue to factor. This was originally a fourth degree polynomial; that means we have 4 solutions.

$(x^2-1)(9x^2+7)=0$

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis. Factoring $(x^2-1)$ gives us that x = 1 and -1. The other set is a bit more tricky. If