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3 years ago

Linear or nonlinear

Mathematics

1 answer:

Wittaler [7]3 years ago

5 0

Answer:

Linear

Step-by-step explanation:

It increases by a steady rate, so it is linear.

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Solve the quadratic equation.<br>m^2/15 -3 = 2

Radda [10]

The answer is $5 \sqrt{3}$

<h3>Explanation :</h3>

$\frac{ {m}^{2} }{15} - 3 = 2$

$\frac{ {m}^{2} }{15} = 2 + 3$

$\frac{ {m}^{2} }{15} = 5$

${m}^{2} = 5 \times 15$

${m}^{2} = 75$

$m = \sqrt{75}$

$m = \sqrt{25 \times 3}$

$m = \sqrt{25} \times \sqrt{3}$

$m = 5 \sqrt{3}$

CMIIW

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3 years ago

Consider this right triangle.<br> 21<br> 29<br> 20<br> Enter the ratio equivalent to s

AleksAgata [21]

Answer:

Part 1) $sin(B)=\frac{21}{29}$

Part 2) $csc(A)=\frac{29}{20}$

Part 3) $cot(A)=\frac{21}{20}$

Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

$sin(B)=\frac{AC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(B)=\frac{21}{29}$

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

$csc(A)=\frac{1}{sin(A)}$

$sin(A)=\frac{BC}{AB}$ -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(A)=\frac{20}{29}$

therefore

$csc(A)=\frac{29}{20}$

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

$cot(A)=\frac{1}{tan(A)}$

$tan(A)=\frac{BC}{AC}$ -----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{20}{21}$

therefore

$cot(A)=\frac{21}{20}$

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3 years ago

In the figure below, EC || AB. Find the length of EC.

timofeeve [1]

Answer:

Letter a)

Step-by-step explanation:

quizlet

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3 years ago

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Taylor ran 57 minutes on Tuesday and 48 minutes on Saturday. Mark ran 62 minutes on Tuesday and 53 minutes on Saturday. Taylor s

marusya05 [52]

Let's compare!

Taylor ran 57 + 48 mins total. Sum would be 105 mins.

Mark ran 62 + 53 mins total. Sum would be 115 mins.

Clearly, the two sums are different when we compare them using subtraction.

115 - 105 = 10. Mark ran 10 mins longer than Taylor.

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Solve (4x^4-7-6x^2) (2x^2 4x^4 8)

kotykmax [81]

Your answer can only be simplified to
256x^10 - 384^8 - 448^6

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3 years ago

Linear or nonlinear​

Linear or nonlinear