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Veronika [31]
3 years ago
7

There is a trapezoid that has an area of 25. If one of its bases is 4 and its other base is 6, what must its height be?

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
7 0
We know that formula to solve for the area of a trapezoid is A=(a+b)/2+h. So, the formula to find the height would be 2*[A/(a+b)]. 
2*[A/(a+b)] Substitute the values for the variables
2*[25/(6+4)] Solve the parentheses
2*(25/10) 
2*2.5=5
The height must be 5.
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AS we know that:

V=SA*h

And we have the volume and we can calculate the SA,,,

So that, we can conclude:
h= \frac{V}{SA} = \frac{323.5}{\pi (7)^2} =2.1015~~in

Are you satisfied?




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