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Alisiya [41]
3 years ago
8

Destiny and Alicia both leave the coffee shop at the same time, but in opposite directions. If Alicia travels 4 mph faster than

Destiny and after 3 hours they are 78 miles apart, how fast is each traveling?
Mathematics
1 answer:
-BARSIC- [3]3 years ago
3 0

Answer: Destiny's speed is 11 mph.

Alicia's speed is 15 mph

Step-by-step explanation:

Destiny and Alicia both leave the coffee shop at the same time, but in opposite directions. If they are 78 miles apart after 3 hours, it means that the total distance that they covered in 3hours is 78 miles

Let x represent the speed at which Destiny travelled. If Alicia travels 4 mph faster than Destiny, it means that the speed at which Alicia travelled is (x + 4) mph

Distance = speed × time

Distance covered by Destiny in 3 hours is

3 × x = 3x

Distance covered by Alicia in 3 hours is

3(x + 4) = 3x + 12

Since the total distance is 78 miles, then

3x + 3x + 12 = 78

6x = 78 - 12 = 66

x = 66/6 = 11 mph

Alicia's speed is

11 + 4 = 15 mph

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Bad White [126]

Answer:

Let v(t) be the velocity of the car t hours after 2:00 PM. Then \frac{v(1/3)-v(0)}{1/3-0}=\frac{50 \:{\frac{mi}{h} }-30\:{\frac{mi}{h} }}{1/3\:h-0\:h} = 60 \:{\frac{mi}{h^2} }.  By the Mean Value Theorem, there is a number c such that 0 < c with v'(c)=60 \:{\frac{mi}{h^2}}. Since v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 60 \:{\frac{mi}{h^2}}.

Step-by-step explanation:

The Mean Value Theorem says,

Let be a function that satisfies the following hypotheses:

  1. f is continuous on the closed interval [a, b].
  2. f is differentiable on the open interval (a, b).

Then there is a number c in (a, b) such that

f'(c)=\frac{f(b)-f(a)}{b-a}

Note that the Mean Value Theorem doesn’t tell us what c is. It only tells us that there is at least one number c that will satisfy the conclusion of the theorem.

By assumption, the car’s speed is continuous and differentiable everywhere. This means we can apply the Mean Value Theorem.

Let v(t) be the velocity of the car t hours after 2:00 PM. Then v(0 \:h) = 30 \:{\frac{mi}{h} } and v( \frac{1}{3} \:h) = 50 \:{\frac{mi}{h} } (note that 20 minutes is 20/60=1/3 of an hour), so the average rate of change of v on the interval [0 \:h, \frac{1}{3} \:h] is

\frac{v(1/3)-v(0)}{1/3-0}=\frac{50 \:{\frac{mi}{h} }-30\:{\frac{mi}{h} }}{1/3\:h-0\:h} = 60 \:{\frac{mi}{h^2} }

We know that acceleration is the derivative of speed. So, by the Mean Value Theorem, there is a time c in (0 \:h, \frac{1}{3} \:h) at which v'(c)=60 \:{\frac{mi}{h^2}}.

c is a time time between 2:00 and 2:20 at which the acceleration is 60 \:{\frac{mi}{h^2}}.

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Step-by-step explanation:

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A bag had 7 orange rocks , 6 green rock , 1 white rock ,7 black rocks , and 2 yellow you randomly pull a rock from the bag ,keep
daser333 [38]

Answer:

Probability = \frac{7}{253}

Step-by-step explanation:

Given

Orange = 7

Green = 6

White = 1

Black = 7

Yellow = 2

Required

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From the question, we understand that the probability is that of without replacement.

Since the yellow, is first picked.

We need to determine the probability of picking a yellow rock, first.

P(Yellow) = \frac{n(Yellow)}{Total}

P(Yellow) = \frac{2}{7 + 6 + 1 + 7 + 2}

P(Yellow) = \frac{2}{23}

The rock has reduced by 1;

Next is to determine the probability of picking an orange rock

P(Orange) = \frac{n(Orange)}{Total - 1}

P(Orange) = \frac{7}{7 + 6 + 1 + 7 + 2- 1}

P(Orange) = \frac{7}{22}

The required probability is calculated as thus:

Probability = P(Yellow) * P(Orange)

Probability = \frac{2}{23} * \frac{7}{22}

Probability = \frac{14}{506}

Probability = \frac{7}{253}

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