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3 years ago

I really need help with these, if you know any it would help so much

Mathematics

1 answer:

algol133 years ago

5 0

Answer:

1: 23.85

2: 83%

3: 44

Step-by-step explanation:

1 - do 53x0.45 (23.85)

2 - Divide 20 by 24, which you get 0.833333333 and move the decimal 2x to the right. You get 83.3333333, but round. So 83%

3 - do 80x0.55 (44)

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Please help Linear equations

svlad2 [7]

Answer:

2 and 4

Step-by-step explanation:

8 0

2 years ago

Which triangle is △ABC similar to and why?

IRISSAK [1]

Answer: The answer is (b) △ABC is similar to △JKL by AA Similarity Postulate .

Step-by-step explanation: We are given a triangle ABC with ∠B = 65° and ∠C = 65°. We are to find the triangle among the other three options which ΔABC similar to.

We can see that in △JKL, we have

∠K = 65° and ∠L = 65°.

Therefore, in ΔABC and ΔJKL, we have

∠B = ∠K,

∠C = ∠L.

So, by AA similarity postulate, we get

ΔABC ≈ ΔJKL.

Thus, the correct option is (b) △ABC is similar to △JKL by AA Similarity Postulate .

3 0

3 years ago

Read 2 more answers

Find the value of x.<br> X =

Paladinen [302]

Answer:

X = 20

Step-by-step explanation:

when you have an angle that looks like an X shape the angles opposite each other are always equal. knowing this we now know that angle 5x must equal 100

so just make X the subject of the formula and solve, like shown bellow

$5x = 100$

$x = 100 \div 5$

$x = 20$

6 0

3 years ago

Please help i have a few more questions like these

Vlada [557]

Answer:

the answer is the last one.

Step-by-step explanation:

add 10 to right and left sides then divide both sides by 4.

7 0

4 years ago

I don’t know how to solve this

Lady_Fox [76]

Answer:

$\theta =2\pi k,\ \ k\in Z\ \\\text{or}\ \\\theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z$

Step-by-step explanation:

Given:

$\cos \theta-\sqrt{3}\sin \theta=1$

Divide this equation by 2:

$\dfrac{1}{2}\cos \theta-\dfrac{\sqrt{3}}{2}\sin \theta=\dfrac{1}{2}$

Note that

$\cos \dfrac{\pi }{3}=\dfrac{1}{2}\\ \\\sin \dfrac{\pi }{3}=\dfrac{\sqrt{3}}{2}$

So, the previous equation is

$\cos \dfrac{\pi}{3}\cdot \cos \theta-\sin \dfrac{\pi}{3}\cdot \sin \theta=\dfrac{1}{2}$

Remind that

$\cos x\cos y-\sin x\sin y=\cos (x+y),$

then

$\cos \left(\dfrac{\pi}{3}+\theta\right)=\dfrac{1}{2}$

The solution of this equation is

$\dfrac{\pi}{3}+\theta=\pm \arccos \dfrac{1}{2}+2\pi k,\ \ k\in Z\\ \\\dfrac{\pi}{3}+\theta=\pm \dfrac{\pi}{3}+2\pi k,\ \ k\in Z\\ \\\theta =2\pi k,\ \ k\in Z\ \text{or}\ \theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z$

8 0

3 years ago