<span>False i believe i think</span>
Answer:
1256
Step-by-step explanation:
Given the function F(x)=1256(1.24)^x, the initial value occurs at x = 0
Substitute x = 0 into the function;
F(0)=1256(1.24)^0
f(0) = 1256(1) (any value raise to sero is 1)
f(0) = 1256
hence the initial value is 1256
Answer:
146.9
Step-by-step explanation:
I'm not sure of the answer but if I'm wrong tell me I'll continue trying it is a pleasure to help you.
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Step-by-step explanation:
m<2
If y = √(2x + 1), then differentiating both sides implicitly with respect to t gives
dy/dt = 1/2 • 1/√(2x + 1) • 2 • dx/dt = 1/√(2x + 1) • dx/dt
(a) If dx/dt = 9 and x = 4, then
dy/dt = 1/√(2•4 + 1) • 9
dy/dt = 1/√(8 + 1) • 9
dy/dt = 1/√9 • 9
dy/dt = 9/3
dy/dt = 3
(b) If dy/dt = 3 and x = 40, then
3 = 1/√(2•40 + 1) • dx/dt
3 = 1/√(80 + 1) • dx/dt
3 = 1/√81 • dx/dt
3 = 1/9 • dx/dt
dx/dt = 27
