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2 years ago

Solve the simultaneous equations: 5x + 2y = 17 4x + y = 10

Mathematics

1 answer:

erik [133]2 years ago

8 0

Answer:

(1, 6 )

Step-by-step explanation:

5x + 2y = 17 → (1)

4x + y = 10 → (2)

Multiplying (2) by - 2 and adding to (1) will eliminate the y- term

- 8x - 2y = - 20 → (3)

Add (1) and (3) term by term to eliminate y

- 3x + 0 = - 3

- 3x = - 3 ( divide both sides by - 3 )

x = 1

Substitute x = 1 into either of the 2 equations and solve for x

Substituting into (1)

5(1) + 2y = 17

5 + 2y = 17 ( subtract 5 from both sides )

2y = 12 ( divide both sides by 2 )

y = 6

solution is (1, 6 )

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What is the best answer to solution of x^2 + 16 = 0?

kolezko [41]

Answer:

4. C. x = 4 or -4

Step-by-step explanation:

since both terms are perfect squares, factor using the difference of squares formula, a² - b² = ( a + b ) ( $\alpha$ - b ) where

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3 years ago

5a+5b=25 and -5a+5b=35

Alex_Xolod [135]

add the two equations together

5a+5b=25

-5a+5b=35

------------------

0 + 10b =60

divide by 10

b=6

5a + 5b = 25

5a +5(6) = 25

5a +30 =25

subtract 30 from each side

5a =-5

divide by 5

a = -1

Answer (-1,6)

or a=-1 b=6

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3 years ago

What is the effect on the graph of the function () =

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Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

I golf club charges $10 to join and

Jobisdone [24]

Answer: He could have played more than 3 games.

Step-by-step explanation:

Hi, to answer this question we have to write an inequality.

I golf club charges $10 to join and $5 per game: So, the cost of playing golf is equal to $10 (joining price) plus the product of the number of games played (x) and the price per game (5).

That expression must be higher than 25, since john paid more than $25.

Mathematically speaking

10+ 5 x > 25

Solving for x

5x >25-10

5x >15

x >15/5

x> 3

He could have played more than 3 games, since his cost was higher ( not equal or higher) than 25.

4 0

3 years ago

Can someone help me the 2nd problem I don’t understand it

Galina-37 [17]

Answer:

So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.

270 miles

Step-by-step explanation:

So is A is going faster than B so A will reach the destination first.

When will A reach it's destination?

Let's find out.

To solve this problem, the following will come in handy:

Speed=distance/time or time*Speed=distance or time=distance/speed .

time=distance/speed

$T_A=\frac{390}{S_A}$

$T_A=\frac{390}{65}$

$T_A=6$

So it will take bus A 6 hours to cover the distance of 390 miles.

How much time would have it taken bus B to reach that same distance?

$T_B=\frac{390}{45}$

$T_B=8.\overline{6}$

So it would have taken bus B $8.\overline{6}$ hours to cover a distance of 390 miles.

So the time difference is $8.\overline{6}-6=2.\overline{6}$ hours.

It will take $2.\overline{6}$ more hours than bus A for bus B to complete a distance of 390 miles.

So bus B traveled $2.\overline{6} \cdot 45=120$ miles (used the time*speed=distance) after bus A got to it's destination.

So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.

4 0

3 years ago