Answer: x = -5, x = 6
<u>Step-by-step explanation:</u>
"Solutions" are also called roots, zeroes, and x-intercepts and are where the parabola crosses the x-axis.
The parabola crosses the x-axis at x = -5 and at x = 6
(see attachment)
What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?
Romashka-Z-Leto [24]
Answer:
The Interquartile range is 10.
Step-by-step explanation:
First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.
So, 23-13=10
The Answer will be 10, the interquartile range is 10.
Hope this helps!
Answer:
w^2*(w+4)*(w^2+10)
Step-by-step explanation:
w^5+4w^4+10w^3+40w^2
w^2*(w^3+4w^2+10w+40)\w^2*(w^2*(w+4)+10(w+4))
w^2*(w+4)*(w^2+10)
Answer: $5 their are 36 donuts and 12 x 3 is 36 and 5 x 3 is 15
Answer:
64.65% probability of at least one injury commuting to work in the next 20 years
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Each day:
Bikes to work with probability 0.4.
If he bikes to work, 0.1 injuries per year.
Walks to work with probability 0.6.
If he walks to work, 0.02 injuries per year.
20 years.
So

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

We want
. Then

In which



64.65% probability of at least one injury commuting to work in the next 20 years