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Alenkinab [10]
3 years ago
7

Line A is represented by the following equation:

Mathematics
2 answers:
Rufina [12.5K]3 years ago
8 0

Answer:

The answer is actually x+y= 4

Step-by-step explanation:

I took the test

8.01

Vesnalui [34]3 years ago
6 0
- for line B so the set of equations to have no solutions bc. x+y=2 and so y=2-x 
so from x+y=4 will result y=4-x

so this is the right equation for line B so the set of equations has no solutions 
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Help please my teacher wont let me leave till im done with this question
ad-work [718]

Answer:

To find the x intercept substitute 0 for y and solve for x. To find the y intercept substitute 0 for x and solve for y.

X intercept: (-2,0)

Y intercept: (0,5/2)

im not sure if you looking for the X and Y intercept for the second equation but if you are the

X intercept: (5/2,0)

Y intercept: (0,-5)

6 0
2 years ago
A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w
DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 21.5, \sigma = 4.7

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.175*4.7

X = 27.0225

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.04*4.7

X = 26.388

The lowest score that would meet the colleges requirement would be decreased to 26.388.

6 0
3 years ago
Which vertex will result in the minimum value of the function T = x - 2y?
PilotLPTM [1.2K]

Answer:

the objective function, P, at each vertex ... Example: Find the maximum and minimum values of P=3x+2y subject to x + 4y ≤ 20 ... We can find the intersection of the two lines.

6 0
3 years ago
Please can someone help me answer the question in the picture
Firdavs [7]
(X+3)(x+7) X+7
————— = ——
(X-3)(x+3) X-3
7 0
2 years ago
Sammy counts the number of people in one section of the school auditorium. He counts 18 female students, 16 male students, and 6
Rzqust [24]

Correct Question:

He counts 18 female students, 16 male students, and 6 teachers. There are

720 people in the auditorium. Consider the probability of selecting one person

at random from the auditorium.

Which of these statements are true?

Choose all that apply.

A:  The probability of selecting a teacher is 6%.

B : The probability of selecting a student is 85%.

C : The probability of selecting a male student is 32%.

D : The probability of selecting a female student is 45%.

Step-by-step explanation:

Option B  and D are correct because

The total number of people in one cross section = 18 + 16 + 6 = 40.

A = The probability of selecting a teacher is = (6/40)x100 = 15 % not equal to 6 %

B = The probability of selecting a male student is = (34/40)x100 = 85%

C = The probability of selecting a male student is = (16/40)x100 = 40 % not equal to 32 %

D : The probability of selecting a female student is = (18/40)x100= 45%

3 0
2 years ago
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