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Blababa [14]
3 years ago
9

WILL MARK BRAINLIEST IF GOTTEN RIGHT IF GOTTEN WRONG ON PURPOSE OR IF YOU DONT KNOW I WILL REPORT YOU :)

Mathematics
2 answers:
Rina8888 [55]3 years ago
8 0

Answer:

B) y = 5

Step-by-step explanation:

10/y = 8/4

8y = 40

y = 5

ludmilkaskok [199]3 years ago
4 0

Answer:

I'm like 99.8 percent sure it's b5

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I need help with this question. Please thanks
NNADVOKAT [17]

Answer:

all you need to do is to multiple

5 0
3 years ago
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A number cube is rolled and a coin is tossed. What is the probability of rolling a number less than 1 and heads?
Fittoniya [83]
I believe it is zero, because there is no number less than 1.
3 0
3 years ago
Which element of variation would not be affected by adding the data value 15 to the data set {3, 5, 6, 8, 9, 10, 13, 14}? A. the
Gwar [14]
B. The median of the data set

**Update; A. The lower quartile**
See other answer for explanation. 
8 0
3 years ago
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Keveni can travel 221/2 miles in 1/3 hours what is his average speed in miles per hour
Alborosie

So I have 2 answers here they are.

key: 1/3hours =20 min

221÷2=110.5÷20=5.525

221.5÷20=11.075

I hope this helps!

6 0
3 years ago
On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John
insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

     $H_{max}=\frac{v^2}{2g}$

     $H_{max} = \frac{(48)^2}{2 \times 12}$

               = 96 ft

b). Time he can stay in the air before hitting the ground is

   $T=\frac{2v}{g}$

  $T=\frac{2 \times 48}{12}$

     = 8 seconds

c).  Considering upward motion as positive direction.

     v = u + at

We find the time taken to reach the maximum height by taking v = 0.

     v = u + at

     0 = 16 + (12) t

     $t=\frac{16}{12}$

        $=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t =  $=\frac{4}{3} \ s$  , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$  feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0
3 years ago
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