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2 years ago

WILL MARK BRAINLIEST IF GOTTEN RIGHT IF GOTTEN WRONG ON PURPOSE OR IF YOU DONT KNOW I WILL REPORT YOU :)

Mathematics

2 answers:

Rina8888 [55]2 years ago

8 0

Answer:

B) y = 5

Step-by-step explanation:

10/y = 8/4

8y = 40

y = 5

ludmilkaskok [199]2 years ago

4 0

Answer:

I'm like 99.8 percent sure it's b5

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Evaluate the polynomial when (a) x = 0 and (b) x=2

Lostsunrise [7]

Step-by-step explanation:

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2 years ago

If rolando earned $28.50 in 2 hours, how much would he earn in 8 hours?

cricket20 [7]

First, we need to find his unit rate, the amount he earns in 1 hour.

So, we have to divide 28.50 by 2.

That is:

28.50 / 2 = $14.25 per hour

To find the amount he earns in 8 hours, we will need to multiply hourly rate found by "8". So,

14.25 * 8 = $114

<h2>Rolando earns $114 in 8 hours</h2>

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1 year ago

Are the triangles similar?

Reil [10]

C. Not similar hope this helps

8 0

2 years ago

HELP!! Algebra help!! Will give stars thank u so much <333

Anna35 [415]

Answers:

Part a) $\bf{\sqrt{x^2+(x^2-3)^2}$
Part b) 3
Part c) 2.24
Part d) 1.58

============================================================

Work Shown:

Part (a)

The origin is the point (0,0) which we'll make the first point, so let (x1,y1) = (0,0)

The other point is of the form (x,y) where y = x^2-3. So the point can be stated as (x2,y2) = (x,y). We'll replace y with x^2-3

We apply the distance formula to say...

$d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(0-x)^2+(0-y)^2}\\\\d = \sqrt{(0-x)^2+(-y)^2}\\\\d = \sqrt{x^2 + y^2}\\\\d = \sqrt{x^2 + (x^2-3)^2}\\\\$

We could expand things out and combine like terms, but that's just extra unneeded work in my opinion.

Saying $d = \sqrt{x^2 + (x^2-3)^2}$ is the same as writing d = sqrt(x^2-(x^2-3)^2)

-------------------------------------------

Part (b)

Plug in x = 0 and you should find the following

$d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(0) = \sqrt{0^2 + (0^2-3)^2}\\\\d(0) = \sqrt{(-3)^2}\\\\d(0) = \sqrt{9}\\\\d(0) = 3\\\\$

This says that the point (x,y) = (0,3) is 3 units away from the origin (0,0).

-------------------------------------------

Part (c)

Repeat for x = 1

$d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(1) = \sqrt{1^2 + (1^2-3)^2}\\\\d(1) = \sqrt{1 + (1-3)^2}\\\\d(1) = \sqrt{1 + (-2)^2}\\\\d(1) = \sqrt{1 + 4}\\\\d(1) = \sqrt{5}\\\\d(1) \approx 2.23606797749979\\\\d(1) \approx 2.24\\\\$

-------------------------------------------

Part (d)

Graph the d(x) function found back in part (a)

Use the minimum function on your graphing calculator to find the lowest point such that x > 0.

See the diagram below. I used GeoGebra to make the graph. Desmos probably has a similar feature (but I'm not entirely sure). If you have a TI83 or TI84, then your calculator has the minimum function feature.

The red point of this diagram is what we're after. That point is approximately (1.58, 1.66)

This means the smallest d can get is d = 1.66 and it happens when x = 1.58 approximately.

6 0

2 years ago

A coin is tossed then a number 1-10 is chosen at random what is the probability of getting heads then a number less than 4

Darya [45]

The probability of getting heads on a coin toss is 0.5
The probability of choosing a number <u>less</u> than four is 3/10 (1,2,3)

Therefore, the probability of getting heads <u>and</u> choosing a number less than four is:
$= \frac{1}{2} (\frac{3}{10}) = \frac{3}{20} = 0.15$

Hope this helps!

3 0

2 years ago