0.732
0.750
If you have trouble with decimals, then multiply both numbers by a constant number to get rid of the decimals. In this case, we would multiply by 1000.
0.732 x 1000 = 732
0.750 x 1000 = 750
Obviously, 750 is bigger than 732. Therefore, 0.75 is bigger than 7.32.
By the way, this is a property:
If
![a \ \textgreater \ b](https://tex.z-dn.net/?f=a%20%5C%20%5Ctextgreater%20%5C%20%20b)
, then
Answer:
1x + 4y = 4 ⇒ 6x + 24y = 24
6x - 8y = 0 ⇒ 6x - 8y = 0
32y = 24
32 32
y = 3/4
x + 4(3/4) = 4
x + 3 = 4
-3 -3
x = 1
(x, y) = (1, 3/4)
Step-by-step explanation:
up there :D
For this case we have the following solution.
x = gallons of water to be added
For the 10% solution we have:
0.1 * 8 = 0.8
Then, for 5% we have:
(0.8 / x + 8) = 0.05
Rewriting:
(0.8 / x + 8) = (5/100)
Answer:
An equation can be used to find x, the humber of gallons of water he should add is:
(0.8 / x + 8) = (5/100)
Step-by-step explanation:
- Let
be the smallest integer
- Let
be the larger integer
As the sum of the reciprocals of the two positive integers is frac 3/16
So,
![\frac{1}{x}\:+\:\frac{1}{2x}\:=\:\frac{3}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%7D%5C%3A%2B%5C%3A%5Cfrac%7B1%7D%7B2x%7D%5C%3A%3D%5C%3A%5Cfrac%7B3%7D%7B16%7D)
![\mathrm{Multiply\:by\:LCM=}16x](https://tex.z-dn.net/?f=%5Cmathrm%7BMultiply%5C%3Aby%5C%3ALCM%3D%7D16x)
![\frac{1}{x}\cdot \:16x+\frac{1}{2x}\cdot \:16x=\frac{3}{16}\cdot \:16x](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%7D%5Ccdot%20%5C%3A16x%2B%5Cfrac%7B1%7D%7B2x%7D%5Ccdot%20%5C%3A16x%3D%5Cfrac%7B3%7D%7B16%7D%5Ccdot%20%5C%3A16x)
Simplify
![24=3x](https://tex.z-dn.net/?f=24%3D3x)
![\mathrm{Switch\:sides}](https://tex.z-dn.net/?f=%5Cmathrm%7BSwitch%5C%3Asides%7D)
![3x=24](https://tex.z-dn.net/?f=3x%3D24)
![\mathrm{Divide\:both\:sides\:by\:}3](https://tex.z-dn.net/?f=%5Cmathrm%7BDivide%5C%3Aboth%5C%3Asides%5C%3Aby%5C%3A%7D3)
![\frac{3x}{3}=\frac{24}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%7D%7B3%7D%3D%5Cfrac%7B24%7D%7B3%7D)
![x=8](https://tex.z-dn.net/?f=x%3D8)
So,
![2x=16](https://tex.z-dn.net/?f=2x%3D16)
<h2>Verification:</h2>
![\frac{1}{8}\:+\:\frac{1}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B8%7D%5C%3A%2B%5C%3A%5Cfrac%7B1%7D%7B16%7D)
![\mathrm{Least\:Common\:Multiplier\:of\:}8,\:16:\quad 16](https://tex.z-dn.net/?f=%5Cmathrm%7BLeast%5C%3ACommon%5C%3AMultiplier%5C%3Aof%5C%3A%7D8%2C%5C%3A16%3A%5Cquad%2016)
![=\frac{2}{16}+\frac{1}{16}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%7D%7B16%7D%2B%5Cfrac%7B1%7D%7B16%7D)
![\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}](https://tex.z-dn.net/?f=%5Cmathrm%7BSince%5C%3Athe%5C%3Adenominators%5C%3Aare%5C%3Aequal%2C%5C%3Acombine%5C%3Athe%5C%3Afractions%7D%3A%5Cquad%20%5Cfrac%7Ba%7D%7Bc%7D%5Cpm%20%5Cfrac%7Bb%7D%7Bc%7D%3D%5Cfrac%7Ba%5Cpm%20%5C%3Ab%7D%7Bc%7D)
![=\frac{2+1}{16}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%2B1%7D%7B16%7D)
![=\frac{3}{16}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3%7D%7B16%7D)
Therefore,
![\frac{1}{8}+\frac{1}{16}=\frac{3}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B8%7D%2B%5Cfrac%7B1%7D%7B16%7D%3D%5Cfrac%7B3%7D%7B16%7D)
Keywords: word problem
, integer
Learn more about solving integer word problem from brainly.com/question/10905225
#learnwithBrainly
Since x = y + 2
so
y + 2 + 4y = 7
5y + 2 = 7
5y = 7-2
5y = 5
y = 1
x= y + 2
x = (1) + 2
x = 3
(x,y) = (3,1)