For this case, what we are going to do first is to assume that all the exams are worth the same percentage of the final grade.
We have then that Lisa's average grade point equation is:
Where,
x: minimum note that lisa must obtain in the last exam.
Clearing x we have:
Answer:
the lowest grade she can get on her last test is:
x = 94
Answer:
h(-6) = 2
Step-by-step explanation:
-x - 4 =
-(-6) - 4 = 2
6-4=2
Answer:
6.4yds if you are finding the hyp
Step-by-step explanation:
5^2+4^2=square root41
square root of 41 is 6.4
Answer:
A. {60°, 120°, 420°}
B. θ = 15π/4; sec(θ) = √2
Step-by-step explanation:
<h3>A.</h3>
The sine function is periodic with period 360°, and it is symmetrical about the line θ = 90°. The reference angle for the given value of sin(θ) is ...
θ = arcsin(√3/2) = 60°
The next larger angle with the same sine is (2×90°) -60° = 120°. Any multiple of 360° added to either one of these angles will give an angle with the same sine. A possible set of 3 angles is ...
{60°, 120°, 420°}
__
<h3>B.</h3>
One degree is π/180 radians, so the given angle in radians is ...
θ = 675° = 675(π/180) radians = 15π/4 radians
This angle has the same trig function values as 7π4, a 4th-quadrant angle with a reference angle of π/4, or 45° The secant of that angle is
sec(45°) = √2
The 4th-quadrant angle has the same sign, so ...
sec(675°) = sec(15π/4) = √2
