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Gemiola [76]
3 years ago
9

Please help me with 16-20

Mathematics
2 answers:
jasenka [17]3 years ago
7 0

Answer:

-4

Step-by-step explanation:

16-20 = -4

Sunny_sXe [5.5K]3 years ago
4 0

Answer:

16 a. -5·4⁻⁴ = -0.01953125

16 b. 7·4⁻³ = 0.109375

Step-by-step explanation:

16 a. -5·4⁻⁴ is the same as -5 / 4⁴ is the same as -5/256

the same applies to b. raise to a negative exponent is the same as placing that factor in a denominator.

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< BAC = 50
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san4es73 [151]

Equivalent expressions are expressions that have the same value, and can be used interchangeably.

The result of the sum 2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) is 4x\sqrt[3]{2y}  + 8x^2y\sqrt[3]{2y^2})

The expression is given as:

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5})

Rewrite the expression as:

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) = 2 (\sqrt[3]{2^4x^3y})  + 4 (\sqrt[3]{3^3 \times 2x^6y^5})

Evaluate the roots

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) = 2 (2x\sqrt[3]{2y})  + 4 (3x^2y\sqrt[3]{2y^2})

Open the brackets

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) = 4x\sqrt[3]{2y}  + 12x^2y\sqrt[3]{2y^2})

The above expression cannot be further simplified.

Hence, the result of the sum 2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) is 4x\sqrt[3]{2y}  + 8x^2y\sqrt[3]{2y^2})

Read more about equivalent expressions at:

brainly.com/question/2972832

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Answer:

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