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nirvana33 [79]
2 years ago
15

Can somebody do this budget form for me?

Mathematics
1 answer:
Rama09 [41]2 years ago
4 0

Answer:8by-step explanation:

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Need help please help me
Ostrovityanka [42]
The solution is the point of intersection between the two equations.

Assuming you have a graphing calculator or a program to lets you graph equations (I use desmos) you simply put in the equetions and note down the coordinates of the point of intersection.

In the graph the first equation is in blue and the second in red.

The point of intersection = the solution = (-6 , -1)



If you dont have access to a graphing calculator you could draw the graphs by hand;

1) Draw a table of values for each equation; you do this by setting three or four values for x and calculating its image in y (you can use any values of x)

y = 0.5 x + 2 (Im writing 0.5 instead of 1/2 because I find its easier in this format)

x | y
-1 | 1.5 * y = 0.5 (-1) + 2 = 1.5
0 | 2 * y = 0.5 (0) + 2 = 2
1 | 2.5 * y = 0.5 (1) + 2 = 2.5
2 | 3 * y = 0.5 (2) + 2 = 3

y = x + 5

x | y
-1 | 4 * y = (-1) + 5 = 4
0 | 5 * y = (0) + 5 = 5
1 | 6 * y = (1) + 5 = 6
2 | 7 * y = (2) + 5 = 7

2) Plot these point on the graph
I suggest to use diffrent colored points or diffrent kinds of point markers (an x or a dot) to avoid confusion about which point belongs to which graph

3) Using a ruler draw a line connection all the dots of one graph and do the same for the other

4) The point of intersection is the solution

8 0
3 years ago
Read 2 more answers
Can anyone please help me!
Alexxx [7]

Answer:

2

Step-by-step explanation:

(4)(−2)+10

=−8+10

=2

5 0
3 years ago
Read 2 more answers
Need help on writing a proof.
viva [34]

Answer: Congruent


Step-by-step explanation:

Line BC is reflexive to itself

AB is congruent to CD, and that's given

Line AC is congruent to BC, using these prior proofs

Angle EDC and Angle FAB are congruent, and that's a given.

You can conclude that they are congruent by AAS



5 0
3 years ago
Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ
Georgia [21]

The y-intercept of a function is the point where the graph crosses the \mathbf{y = x^3 + 2x^2 - 193x - 270 }

  • The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
  • The y-intercept is -13.5
  • The standard equation of the function is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

\mathbf{x = 10}

\mathbf{x = -3}

\mathbf{x = -9}

Equate the above points to 0

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

<u>(b) The y-intercept</u>

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

<u>(c) The standard form</u>

In (a), we have:

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Multiply the above equations

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }

Expand

\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }

\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }

Expand

\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }

Collect like terms

\mathbf{x^3 + 12x^2 - 10x^2+ 27x  - 220x - 270 = 0 }

\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }

Replace 0 with y

\mathbf{y = x^3 + 2x^2 - 193x - 270 }

Hence, the standard form is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

Read more about graphs and functions at:

brainly.com/question/18806107

3 0
3 years ago
The measures of the angles of A ABC are given by the expressions in the table.
Westkost [7]

First You add all given angles up to equal 180 to give you x then you plug x into equations

A= 125 degrees

C= 35 degrees

4 0
3 years ago
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