Answer:
Step-by-step explanation:
Hope this helps!
The first one and the third one are correct. because for the when you plug 1 on the first piece wise function you get 3.
f(3) =1. and f(1)=3 so f(1)>f(3)
Answer:
0.7999989281
Step-by-step explanation:
x1 = cos^-1 (3/5)
x1= 53.13°
sin(53.13) = 0.7999989281
It is given in the question that the stands of the soccer field has the capacity to hold 40 people. Also it is given that the stands of the soccer field is 3/4 filled.
Then,
The number of people in the stands = 40 * (3/4)
= 30
So 30 people are in the stands of the soccer field.
Now among the people present in the stands of the soccer field, 5/6 are home fans and the rest are fans of the away team.
Then,
Number of home team fans = 30 * (5/6)
= 25
So there are 25 home team fans present in the stand of the soccer field.
Answer:
The probability that a household has at least one of these appliances is 0.95
Step-by-step explanation:
Percentage of households having radios P(R) = 75% = 0.75
Percentage of households having electric irons P(I) = 65% = 0.65
Percentage of households having electric toasters P(T) = 55% = 0.55
Percentage of household having iron and radio P(I∩R) = 50% = 0.5
Percentage of household having radios and toasters P(R∩T) = 40% = 0.40
Percentage of household having iron and toasters P(I∩T) = 30% = 0.30
Percentage of household having all three P(I∩R∩T) = 20% = 0.20
Probability of households having at least one of the appliance can be calculated using the rule:
P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)
P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20 P(at least one of the three) = 0.95
The probability that a household has at least one of these appliances is 0.95
