So I just did 3x-20=223
3x=243
x=243/3
x=81
so the answer would be 81
Answer:
https://tex.z-dn.net/?f=q%3D0%2C%5C%20r%3D2%2C%5C%20s%3D3%2C%5C%20t%3D-3
Answer:
0.15866 is the probability of the average fracture strength of selected 100 pieces of glasses that of exceed 14.3.
Step-by-step explanation:
Given that, the strength of a tempered(x) a glass has average 14.1 and has standard deviation 2.
, 
n=number of selected pieces= 100.
The probability that the average fracture strength of 100 pieces of this glass exceed 14.3 is



= 1 - 0.84134
=0.15866.
Answer:
On the graphing calculator, use the function normCdf, where
- lower bound = -9999
- upper bound = 210
- mean = 250
- standard deviation = 46
It will result in normCdf(-9999,210,250,46) ≈ 0.192269 or 19.2269%