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3 years ago

How many solutions does 6 - 3x = 4 - x - 3 - 2x have?

Mathematics

1 answer:

White raven [17]3 years ago

7 0

Answer:

No Solution

Step-by-step explanation:

6 - 3x = 4 - x - 3 - 2x (Given)

6 - 3x = -1 -3x (combine like terms)

7 (addition)

The x cancels each other out so no solution.

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0.25:1.5 in simplest form

Lelechka [254]

The answer should be
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.16

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3 years ago

Which equation represents a line that passes through (2, - 1/2) and has a slope of 4 ?

solmaris [256]

Answer:

y=4x-8.5

Step-by-step explanation:

Use point- slope form, since you are given one point and one slope.

y-y₁=m(x-x₁)

Plug coordinates and slope in.

y-(-1/2)=4(x-2)

Solve

y+1/2=4x-8

y=4x-8.5

7 0

3 years ago

Please help me and show your work thank you

Furkat [3]

Answer:

She has walked 7233.6 ft

Step-by-step explanation:

13.7 miles ÷ 10 = 1.37 miles

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5280 x 1.37 = 7233.6 ft (or 7234 if rounded to the nearest ft)

6 0

3 years ago

How many solutions does the equation have?

timurjin [86]

$4(2x+3)=2(3x-4)\\
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7 0

3 years ago

Read 2 more answers

Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon

leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = proportion of households that have three cell phones NOT known.

So, Null Hypothesis, $H_0$ : p = 30% {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, $H_A$ : p $\neq$ 30% {means that the actual percentage of households different from 30%}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of households having three cell phones = $\frac{43}{150}$ = 0.29

n = sample of households = 150

So, the test statistics = $\frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }$

= -0.27

The value of z test statistic is -0.27.

Also, P-value of the test statistics is given by;

P-value = P(Z < -0.27) = 1 - P(Z $\leq$ 0.27)

= 1 - 0.6064 = 0.3936

Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0

3 years ago