B)hydrogen ...................
Smaller diagonal is 4.453 and longer diagonal is 10
If the two sides of a parallelogram are a and b and acute angle between the sides is θ,
the smaller diagonal is √a2+b2−2abcosθ
and longer diagonal is √a2+b2+2abcosθ
Hence in the given case
Smaller diagonal is √3.72+6.82−2×3.7×6.8×cos48∘
= √13.69+46.24−50.32×0.66913
= √59.93−40.101
= √19.829
= 4.453
Longer diagonal is √3.72+6.82+2×3.7×6.8×cos48∘
= √13.69+46.24+50.32×0.66913
= √59.93+40.101
= √100.031
= 10
Answer:
The numbers, positive, negative signs and the symbol of elements are used to represent the ions.
Explanation:
Steps to write the ions:
- Write the symbol of an element. For example in case of magnesium we would write Mg.
- In second step write the number of electrons in superscript that are lost or gained by an atom. For example magnesium atom loses two electrons written as followed, Mg².
- In third step write the charge as superscript after the numbers. For example, magnesium loses two electrons that's why we put the positive sign after 2, because by losing the electrons cations are formed. Mg²⁺
- If the atom of an element lose or gain only one electron then 1 is omitted and only the negative or positive sign are written on superscript. For example in case of sodium cation and chlorine anion, Na⁺ , Cl⁻.
Answer:
663 g
Explanation:
Step 1: Write the balanced equation
2 LiOH + CO₂ ⇒ H₂O + Li₂CO₃
Step 2: Calculate the moles corresponding to 825 L of CO₂
At standard pressure and temperature, 1 mole of CO₂ has a volume of 22.4 L.
825 L × 1 mol/22.4 L = 36.8 mol
Step 3: Calculate the moles of H₂O formed from 36.8 moles of CO₂
The molar ratio of CO₂ to H₂O is 1:1. The moles of H₂O formed are 1/1 × 36.8 mol = 36.8 mol.
Step 4: Calculate the mass corresponding to 36.8 moles of H₂O
The molar mass of H₂O is 18.02 g/mol.
36.8 mol × 18.02 g/mol = 663 g