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Savatey [412]
3 years ago
14

Students investigating the reaction between CH3COOH and NaHCO3 obtain .80 g of CO2 from the reaction. Their theoretical yield wa

s 1.0 g. What was their percent yield?

Chemistry
1 answer:
stellarik [79]3 years ago
8 0

Answer:

If the actual yield was .80g, and the IDEAL (100%) yield is 1.0g, then put it in the equation & you’ll get 80% yield.

Explanation:

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7 0
3 years ago
Which of the following are lost or gained during a nuclear reaction?
hram777 [196]

Answer:

I think that is electrons and nucleus

Explanation:

It makes sense

5 0
3 years ago
Read 2 more answers
Calculate the mass percentage of oxygen in dry air
grigory [225]
              <span> (0.20948 x 31.998) / (
(0.78084 x 28.013) +
(0.20948 x 31.998) +
(0.00934 x 39.948) +
(0.000375 x 44.0099) +
(0.00001818 x 20.183) +
(0.00000524 x 4.003) +
(0.000002 x 16.043) +
(0.00000114 x 83.80) +
(0.0000005 x 2.0159) +
(0.0000005 x 44.0128) ) = 0.23140 = 23.140% O by mass </span>
5 0
4 years ago
Read 2 more answers
How many grams of P4O10 (292.88 g/mol) form when phelpsphorous (P4, 125.52 g/mol) reacts with 16.2 L of O2 (33.472 g/mol) ) at s
nevsk [136]

Answer:

40.5 g of P₄O₁₀ are produced

Explanation:

We state the reaction:

P₄ + 5O₂ → P₄O₁₀

We do not have data from P₄ so we assume, it's the excess reactant.

We need to determine mass of oxygen and we only have volumne so we need to apply density.

Density = mass / volume, so Mass = density . volume

Denstiy of oxygen at STP is: 1.429 g/L

1.429 g/L . 16.2L = 23.15 g

We determine the moles: 23.15 g . 1mol / 33.472g = 0.692 moles

5 moles of O₂ can produce 1 mol of P₄O₁₀

Our 0.692 moles may produce (0.692 . 1)/ 5 = 0.138 moles

We determine the mass of product:

0.138 mol . 292.88 g/mol = 40.5 g

3 0
3 years ago
How many molecules (or formula units) are in 138.56 g C4H10 Express your answer using four significant figures.
Semenov [28]

Answer:

dont buy cheap and off we went

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