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Savatey [412]
3 years ago
14

Students investigating the reaction between CH3COOH and NaHCO3 obtain .80 g of CO2 from the reaction. Their theoretical yield wa

s 1.0 g. What was their percent yield?

Chemistry
1 answer:
stellarik [79]3 years ago
8 0

Answer:

If the actual yield was .80g, and the IDEAL (100%) yield is 1.0g, then put it in the equation & you’ll get 80% yield.

Explanation:

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what is the molecular formula for a compound with the empirical formula: K2SO4 and a molecular mass of 696g​
LekaFEV [45]

Answer:

K8S4O16 or K8(SO4)4 depending on if the SO4 is supposed to represent sulfate or not

Explanation:

Find the molar mass of K2SO4 first:

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Divide the goal molar mass of 696 by the molar mass of the empirical formula:

696 / 174 = 4

This means you need to multiply everything in the empirical formula by 4:

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3 years ago
6) A 0.20 ml CO2 bubble in a cake batter is at 27°C. In the oven it gets
Nata [24]

Answer: The new volume of cake is 1.31 mL.

Explanation:

Given: V_{1} = 0.20 mL,         T_{1} = 27^{o}C

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Formula used to calculate new volume is as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{0.20 mL}{27^{o}C} = \frac{V_{2}}{177^{o}C}\\V_{2} = 1.31 mL

Thus, we can conclude that the new volume of cake is 1.31 mL.

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