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Savatey [412]
3 years ago
14

Students investigating the reaction between CH3COOH and NaHCO3 obtain .80 g of CO2 from the reaction. Their theoretical yield wa

s 1.0 g. What was their percent yield?

Chemistry
1 answer:
stellarik [79]3 years ago
8 0

Answer:

If the actual yield was .80g, and the IDEAL (100%) yield is 1.0g, then put it in the equation & you’ll get 80% yield.

Explanation:

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2 years ago
Calculate the Kelvin temperature to which 10.0 L of a gas at 27 °C would have to be heated to change the volume to 12.0 L. Units
KatRina [158]

Hello!

For this problem, we will be applying <em>Charles' Law</em>:

V1/T1 = V2/T2

Now that we have the formula, let's convert the temperature to Kelvin.

27 + 273 = 300K

Let's plug everything in now!

10/300 = 12.0/x

Simplified:

1/30 = 12.0/x

Cross-multiply:

1x = 30*12.0

<u>x = 360</u>

<em>Check!</em>

10/300 = 12/360

300*12 = 360*10

3600 = 3600

Therefore, you would have to heat the gas at a temperature of 360K in order to raise the volume to 12.0L.

 

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