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Radda [10]
3 years ago
9

Select the substance that is thought to be partially responsible for depleting the concentration of ozone in the stratosphere. s

elect the substance that is thought to be partially responsible for depleting the concentration of ozone in the stratosphere. o2 cfcl3 n2 he co2
Chemistry
1 answer:
gogolik [260]3 years ago
6 0

Answer:

cfcl3

Explanation:

When the cfcl3 in the atmosphere is hit by UV rays from the sun, it decomposes to Cl atoms. These Cl atoms then react with the ozone producing O2 and ClO. The ClO bombard with O atoms splitting the ClO up and the free Cl atom again bonds to another O3 molecule hence reducing it. One ClO can reduce several O3 molecules (up to 100,000) creating an ozone hole.

2Cl + O3 → 2ClO + 2O2

2ClO + 2O → 2Cl + 2O2

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D. 100 I hope this help :)
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2 years ago
Si uno pone un hilo en un hielo y un poco de sal el hilo se levanta el hilo con el hielo. Por que sé relaciona con calor y tempe
777dan777 [17]

Answer:

Explanation:

El hielo encierra la primavera antes de espolvorear la sal.

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3 0
3 years ago
A) Briefly discuss hydrolysis of sicl4​
Stolb23 [73]

Answer:

Types of Hydrolysis

There are several types of hydrolysis, and we will look at them in brief below.

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Acid and Base: Acid–base-catalysed hydrolysis can be found during the hydrolysis of esters or amides. Here, the process of hydrolysis occurs when water or hydroxyl ion reacts with the carbon of the carbonyl group of the ester or amide where new compounds are formed. The products of both hydrolysis are compounds with carboxylic acid groups.

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Explanation:

8 0
3 years ago
Kernels of corn are heated and become popcorn. Why is this a chemical change?
goldfiish [28.3K]

Answer:

When popcorn is popped, liquid inside the kernel is changed to steam. Pressure from the steam builds up inside the kernel. When the pressure reached a critical stage the kernel pops turning itself inside out. This is a physical change.

Explanation:

6 0
2 years ago
Read 2 more answers
A sample of methane (CH4) has a volume of 25 mL at a pressure of 0.80 atm. What is the volume of the gas at each of the followin
Xelga [282]

Answer:

a. 50ml b.10ml c. 6.097ml d. 190.1 ml

Explanation:

According to Boyle's law

Volume is inversely proportional to pressure at constant temerature

Mathematically

P1V1=P2V2

P1=Initial pressure=0.8atm

V1=Initial volume=25ml

making V2 the subject

at 0.4atm P2=0.4 atm,

V2=25×0.8/0.4

=50ml

at 2 atm V2=25×0.8/2

=10 ml

1mmHg=0.00131579

2500mmHg=3.28 atm

At 3.28 atm,V2=25×0.8/3.28

=6.097 ml

at 80.0 torr

1 torr=0.00131579

80 torr=0.1052 atm

at 0.1048 atm V2=25×0.8/0.1048

=190.1 ml

4 0
3 years ago
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