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Radda [10]
4 years ago
9

Select the substance that is thought to be partially responsible for depleting the concentration of ozone in the stratosphere. s

elect the substance that is thought to be partially responsible for depleting the concentration of ozone in the stratosphere. o2 cfcl3 n2 he co2
Chemistry
1 answer:
gogolik [260]4 years ago
6 0

Answer:

cfcl3

Explanation:

When the cfcl3 in the atmosphere is hit by UV rays from the sun, it decomposes to Cl atoms. These Cl atoms then react with the ozone producing O2 and ClO. The ClO bombard with O atoms splitting the ClO up and the free Cl atom again bonds to another O3 molecule hence reducing it. One ClO can reduce several O3 molecules (up to 100,000) creating an ozone hole.

2Cl + O3 → 2ClO + 2O2

2ClO + 2O → 2Cl + 2O2

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3 years ago
An aqueous solution of perchloric acid is standardized by titration with a 0.191 M solution of barium hydroxide. If 13.8 mL of b
WARRIOR [948]

Answer:

Molarity of HClO_{4} solution is 0.311 M

Explanation:

Neutralization reaction: 2HClO_{4}+Ba(OH)_{2}\rightarrow Ba(ClO_{4})_{2}+2H_{2}O

According to balanced reaction, 1 mol of Ba(OH)_{2} neutralizes 2 moles of HClO_{4}

Number of moles of Ba(OH)_{2} in 13.8 mL of 0.191 M Ba(OH)_{2} solution = \frac{0.191}{1000}\times 13.8moles = 0.00264moles

Let's assume molarity of HClO_{4} solution is C (M) then-

Number of moles of HClO_{4} in 17.0 mL of C (M) HClO_{4} solution = \frac{C}{1000}\times 17.0moles = 0.017Cmoles

Hence, 0.017C=(2\times 0.00264)

         or, C=0.311

So, molarity of HClO_{4} solution is 0.311 M

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3 years ago
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Calculate the molar mass of the following compounds in g/mol.<br> CH3CO2H
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Answer:

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Explanation:

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