Using Pythagorean theorem, the student walked 53.58 meters more compared to the total displacement from the starting point.
If a student walks 100 meters north, then 100 meters west, then the path he travels resembles the sides of a right triangle (see attached photo).
Using Pythagorean theorem, we can solve for the total displacement from the starting point to the end point.
c^2 = a^2 + b^2
where c is the total displacement from the starting point to the end point
a is the distance he walks up north
b is the distance he walks to the west
c^2 = 100^2 + 100^2
c^2 = 10,000 + 10,000
c^2 = 20,000
c = 141.42 meters
Comparing the total distance the student walked and the total displacement from the starting point to the end point by subtraction.
100 meters + 100 meters - 141.42 meters = 53.58 meters
Learn more about Pythagorean Theorem here: brainly.com/question/343682
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Answer:
10.4 cm
Step-by-step explanation:
Since the area is half of the base multiplied by the height A = 1/2 * b * h, the height can be found from h = 2A/b
h = (2 * 83.72 )/16.1 = 10.4
Answer:
5 yd
Step-by-step explanation:
Use Pythagorean theorem,
Hypotenuse² = base² + altitude²
= 3² + 4²
= 9 + 16
= 25
Hypotenuse = √25 = √5*5 = 5 yd