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3 years ago

Consider 4 g N2O5, in a test tube. [Given: Ar(N) = 14, Ar(O) = 16]

Chemistry

1 answer:

likoan [24]3 years ago

4 0

Answer:

74.08%

Explanation:

We'll begin by calculating the mass of

Oxygen in 4 g of N₂O₅. This can be obtained as follow:

Molar mass of N₂O₅ = (14×2) + (16×5)

= 28 + 80

= 108 g/mol

Mass of oxygen in N₂O₅ = 5 × 16 = 80 g

Mass of oxygen in 4 g of N₂O₅

= 80 / 108 × 4

= 2.963 g

Finally, we shall determine the percentage of oxygen in 4 g of N₂O₅. This can be obtained as follow:

Mass of oxygen = 2.963 g

Mass of N₂O₅ = 4 g

Percentage of oxygen =?

Percentage of oxygen = mass of oxygen / mass of N₂O₅ × 100

Percentage of oxygen = 2.963 / 4 × 100

Percentage of oxygen = 74.08%

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spayn [35]

Answer:

0.571 mol

Explanation:

Given data:

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Solution:

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Goryan [66]

Answer:

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Answer:

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Explanation:

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I hope it helps you!

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