Answer:
The solutions should be added in this order NaCl > Na2SO4 > Na2S
Explanation:
Silver is insoluble as a chloride, so the silver ions get precipitated on addition of chloride ion as silver chloride. This means Ag+ would be removed the first.
So we will add NaCl in the first step.
The following reaction will occur.
Ag+ + Cl- → AgCl(s)
Both, Pb2 and Ni are soluble as chlorides. (lead chloride is soluble as a hot solution but will ppt when colder).
When we add Na2SO4, Pb2+ will get precipitated (because it's insoluble) as PbSO4 and Ni will remain soluble as NiSO4 is soluble in water.
The reaction that will occur is:
Pb^2+ + SO4^2- → PbSO4(s)
Nickel is insoluble as a sulfide. So when we will add Na2S, nickel will be precipitated as sulfide and be able to separate and be collected.
The solutions should be added in this order NaCl > Na2SO4 > Na2S
Answer:
NH₄CN, NH₄IO₃, Fe(CN)₃, Fe(IO₃)₃
Explanation:
Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.
1.) NH₄CN
-----> NH₄⁺ and CN⁻
-----> +1 + (-1) = 0
2.) NH₄IO₃
-----> NH₄⁺ and IO₃⁻
-----> +1 + (-1) = 0
3.) Fe(CN)₃
-----> Fe³⁺ and CN⁻
-----> +3 + (-1) + (-1) + (-1) = 0
4.) Fe(IO₃)₃
-----> Fe³⁺ and IO₃⁻
-----> +3 + (-1) + (-1) + (-1) = 0
It is Sublimation.I hope this helps