Answer:
is the correct answer to the given question.
Explanation:
Given k=6.40 x 10-3 min-1.
According to the first order reaction .
The concentration of time can be written as
![[\ A\ ]\ = \ [\ A_{0}\ ] * e \ ^\ {-kt}](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D%5C%20%3D%20%5C%20%5B%5C%20%20A_%7B0%7D%5C%20%5D%20%20%2A%20e%20%5C%20%5E%5C%20%20%7B-kt%7D)
Here ![[\ A\ ]_{0}](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D_%7B0%7D)
= Initial concentration.
So ![[\ A\ ]_{0}= 0.0314 M](https://tex.z-dn.net/?f=%5B%5C%20A%5C%20%5D_%7B0%7D%3D%200.0314%20M)
Putting this value into the above equation.
=0.211 M
This can be written as
Answer:
48 g S
Explanation:
Step 1: Define
Molar Mass of Sulfur (S) - 32.07 g/mol
Step 2: Use Dimensional Analysis
= 48.105 g S
Step 3: Simplify
We have 2 sig figs.
48.105 g S ≈ 48 g S
3. A
4. B
5. A
6. E
7. A
8. C
9. A
10. B
Some of these were guesses but they were educated guesses. Best of luck. If some of them are wrong I am sorry. <span />
Answer:
Molecules that will have dipole-dipole forces with like molecules include the water (H2O) molecule. Another example is the Hydrogen Chloride (HCl) molecule.
Explanation:
Intermolecular forces are forces of attraction or repulsion that exist between particles (ions, atoms, or molecules) that are close/in nearby proximity to each other. Usually, intermolecular forces are not as strong as intramolecular forces which create covalent or ionic bonds between the atoms that exist within molecules. Dipole-dipole interactions occur whenever the partial charges that exist within one molecule are attracted to the opposite partial charges that exist within another different molecule that is nearby and similar in composition: the positive end/charges of one molecule are attracted to the negative end/charges of another similar molecule.
An example of molecules that exhibit dipole-dipole interaction is the water (H2O) molecule. Another molecule which exhibits dipole–dipole interaction is the Hydrogen Chloride (HCl) molecule, whereby the positive end of one HCl molecule usually attracts the negative end of another HCl molecule.
