Answer:
The slope is: m = -²/₅
The y-intercept is: b = -2
The equation of the line: y = -²/₅x - 2
Step-by-step explanation:
The equation of a line in slope intercept form: y = mx + b
The slope: 
(-5, 0) ⇒ x₁ = -5, y₁ = 0
(0, -2) ⇒ x₂ = 0, y₂ = -2
So:

Answer:
2 dollars?
Step-by-step explanation:
8 divided by 4
Answer:
5 units
Step-by-step explanation:
Image of the trapezoid is attached.
To find the height of the trapezoid (image attached), let's take the formula for area of a trapezoid.
The formula for area of a trapezoid is:

Here, a and b represents the bases of the trapezoid.
a = 6
b = 10
h which represents height is unknown.
A = 40
Substitute figures:



Solve for h:


The height of the trapezoid is 5 units
Answer:
$10.23
Step-by-step explanation:
$2.19+$1.39+$3.69+$2.29=9.56
9.56 x 1.07=10.2292
You round to the nearest tenths place
$10.23
Answer:
Option B and D are correct
Step-by-step explanation:
Exponential functions are really useful in the real world situation. They can be used to solve following
a) Population Models
b) Determination of area and perimeters
c) Determine time related things such as half life, time of happening of an event etc.
d) Useful for solving financial problems such as computing investments etc.
Hence, option B and D