18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.
<u>Step-by-step explanation:</u>
Let x = kg of 15% copper alloy
Let y = kg of 60% copper alloy
Since we need to create 90 kg of alloy we know:
x + y = 90
51% of 90 kg = 45.9 kg of copper
So we're interested in creating 45.9 kg of copper
We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:
0.15x + 0.60y = 45.9
but
x + y = 90
x= 90 - y
substituting that value in for x
0.15(90 - y) + 0.60y = 45.9
13.5 - 0.15y + 0.60y = 45.9
0.45y = 32.4
y = 72
Substituting this y value to solve for x gives:
x + y = 90
x= 90-72
x=18
Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.
M^2 - 2mn + n^2
(-2)^2 -2(-2)(4) + 4^2
4 + 16 + 16
36
Answer:
x + 5 * 4
In this problem we have to transfer the expression from verbal to mathematical language. Which would be:
x + 5 * 4
"x" represents "a number"
"5 more than a number" is represented by "x + 5"
"the product of" is indicating a multiplication, which is represented by "*"
Hope it helped,
BioTeacher101
Answer:
Base area = 25.2 in^2
Step-by-step explanation:
Base area = 63/2.5 = 25.2 in^2
Answer:
300 gm
Hope I helped :)
Step-by-step explanation:
