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musickatia [10]

3 years ago

14

A rectangular park has an area of 64 square yards. If we multiply its length and width by 12, what will be the area of the new r

ectangle?

2 answers:

erma4kov [3.2K]3 years ago

7 0

The area of the rectangle would be 768

Strike441 [17]3 years ago

3 0

Answer:

i think it is 1642 but im not totally sure im so sorry if its wrong

Step-by-step explanation:

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Help me with this question please

Dmitry_Shevchenko [17]

$481, let me know if you want the solution with the work.

3 0

3 years ago

5. Thunderstorms are more common in some areas than in others. The map shows the average number of thunderstorms per year in dif

natta225 [31]

Answer:

where is the map?

Step-by-step explanation:

4 0

2 years ago

*FIRST PERSON TO GET IT RIGHT AND ANSWER FIRST GETS BRAINLIEST*

polet [3.4K]

There are 23 sharks and 7 octopi in the aquarium

Let the number of sharks in the aquarium be x

Let the number of octopi in the tank be y

If the total number of animals in the tank is 30, therefore;

x + y = 30 ....................... 1

If the total number of legs in the tank is 171 with starfish having 5 legs and Octopus having 8 legs, the required expression will be:

5x + 8y = 171 ................ 2

From equation 1, x = 30 - y ................... 3

Substitute equation 3 into 2 to have:

5(30-y) + 8y = 171

150 - 5y + 8y = 171

3y = 171 - 150

3y = 21

y = 7

Recall that x = 30 - y

x = 30 - 7

x = 23

Hence there are 23 sharks and 7 octopi in the aquarium

Learn more on simultaneous equation here: brainly.com/question/148035

8 0

2 years ago

I will give brainliest

alex41 [277]

Answer:

x = 1.25

y = 1.75

Step-by-step explanation:

Since, the line that is 8 units long is parallel to the line that is ten units long.

Therefore, both the triangles are similar by AA postulate.

Corresponding sides of of the similar triangles are in proportion.

Therefore,

$\frac{5}{x + 5} = \frac{7}{y + 7} = \frac{8}{10} \\ \\ \implies \frac{5}{x + 5} = \frac{8}{10} \\ \\ 5 \times 10 = 8(x + 5) \\ \\ 50 = 8x + 40 \\ \\ 50 - 40 = 8x \\ \\ 10 = 8x \\ \\ \frac{10}{8} = x \\ \\ x = 1.25 \\ \\ \\ \frac{7}{y + 7} = \frac{8}{10} \\ \\ 7 \times 10 = 8(y + 7) \\ \\ 70 = 8y + 56 \\ \\ 70 - 56 = 8y \\ \\ 14 = 8y \\ \\ \frac{14}{8} = y \\ \\ y = 1.75$

3 0

2 years ago

Compute the line integral with respect to arc length of the function f(x, y, z) = xy2 along the parametrized curve that is the l

SIZIF [17.4K]

Answer:

$\displaystyle\frac{15\sqrt{3}}{4}-90\sqrt{146}$

Step-by-step explanation:

The line integral with respect to arc length of the function f(x, y, z) = xy2 along the parametrized curve that is the line segment from (1, 1, 1) to (2, 2, 2) followed by the line segment from (2, 2, 2) to (−9, 6, 5) equals the sum of the line integral of f along each path separately.

Let

$C_1,C_2$

be the two paths.

Recall that if we parametrize a path C as $(r_1(t),r_2(t),r_3(t))$ with the parameter t varying on some interval [a,b], then the line integral with respect to arc length of a function f is

$\displaystyle\int_{C}f(x,y,z)ds=\displaystyle\int_{a}^{b}f(r_1,r_2,r_3)\sqrt{(r'_1)^2+(r'_2)^2+(r'_3)^2}dt$

Given any two points P, Q we can parametrize the line segment from P to Q as

r(t) = tQ + (1-t)P with 0≤ t≤ 1

The parametrization of the line segment from (1,1,1) to (2,2,2) is

r(t) = t(2,2,2) + (1-t)(1,1,1) = (1+t, 1+t, 1+t)

r'(t) = (1,1,1)

and

$\displaystyle\int_{C_1}f(x,y,z)ds=\displaystyle\int_{0}^{1}f(1+t,1+t,1+t)\sqrt{3}dt=\\\\=\sqrt{3}\displaystyle\int_{0}^{1}(1+t)(1+t)^2dt=\sqrt{3}\displaystyle\int_{0}^{1}(1+t)^3dt=\displaystyle\frac{15\sqrt{3}}{4}$

The parametrization of the line segment from (2,2,2) to

(-9,6,5) is

r(t) = t(-9,6,5) + (1-t)(2,2,2) = (2-11t, 2+4t, 2+3t)

r'(t) = (-11,4,3)

and

$\displaystyle\int_{C_2}f(x,y,z)ds=\displaystyle\int_{0}^{1}f(2-11t,2+4t,2+3t)\sqrt{146}dt=\\\\=\sqrt{146}\displaystyle\int_{0}^{1}(2-11t)(2+4t)^2dt=-90\sqrt{146}$

Hence

$\displaystyle\int_{C}f(x,y,z)ds=\displaystyle\int_{C_1}f(x,y,z)ds+\displaystyle\int_{C_2}f(x,y,z)ds=\\\\=\boxed{\displaystyle\frac{15\sqrt{3}}{4}-90\sqrt{146}}$

8 0

2 years ago