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musickatia [10]

3 years ago

14

A rectangular park has an area of 64 square yards. If we multiply its length and width by 12, what will be the area of the new r

ectangle?

2 answers:

erma4kov [3.2K]3 years ago

7 0

The area of the rectangle would be 768

Strike441 [17]3 years ago

3 0

Answer:

i think it is 1642 but im not totally sure im so sorry if its wrong

Step-by-step explanation:

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What is a histogram?

olasank [31]

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A histogram is a graph that organizes a group of data points. A histogram graphically summarize the distribution of a univariate data set.

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3 years ago

Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y

mariarad [96]

Answer:

the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

$\frac{\pi }{2} [e^2 - 1 ]$ or 10.036

Step-by-step explanation:

Given the data in the question;

y = $y = e^{(x - 1 )$ , y = 0, x = 1, x = 2.

Now, using the integration capabilities of a graphing utility

y = $y = e_2}^{(x - 1 )_$ , y = 0

Volume = $\pi \int\limits^2_1 ( e^{x-1)^2} - (0)^2 dx$

Volume = $\pi \int\limits^2_1 ( e^{x-1)^2 dx$

Volume = $\pi \int\limits^2_1 e^{2x-2}dx$

Volume = $\frac{\pi }{e^2} \int\limits^2_1 e^{2x}dx$

Volume = $\frac{\pi }{e^2} [\frac{e^{2x}}{2}]^2_1$

Volume = $\frac{\pi }{2e^2} [e^4 - e^2 ]$

Volume = $\frac{\pi }{2} [e^2 - 1 ]$ or 10.036

Therefore, the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

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3 years ago

Suppose f(x)=4x-2 and g(x)=-2x+1

choli [55]

In order to get g(x) you would multiply the equation of f(x) by -1/2.
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2 years ago

What is the value of x in the equation 4(–5 + x) = –4?

kenny6666 [7]

Answer:

C. 4

Please give me brainliest if you can, thank you :)

Step-by-step explanation:

4(-5+x)= -4

-20+4x= -4

+20 +20

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/4 /4

x= 4

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2 years ago

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Lynna [10]

The answer is 166
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2 years ago

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