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3 years ago

For the equation : y = 2x + 10. Write any two possible solutions in ordered form. (Hint: e.G ( 4, 18))

Mathematics

2 answers:

nalin [4]3 years ago

5 0

Answer:

(0, 10)

and

(1, 12)

babunello [35]3 years ago

4 0

Answer:

(0,-10) and (1,-12)

Step-by-step explanation:

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The mode is the value of the data point that appears the most often. What is the mode?

Pachacha [2.7K]

the mode :is the most repeated value
for example if the question asked you to find the mode among a set of numbers like:2,3,2,4,5,5,2
the mode will be 2 because 2 is the most repeated value

5 0

2 years ago

Calculate the amount and compound interest on Rs 5000 compounded annually or 2 years 6 months at the rate of 10% per annum.

cluponka [151]

Answer:

Amount

Rs 6345.30

Compound interest

Rs 1,345.30

Step-by-step explanation:

Here in this question, we are interested in calculating the amount and the compound interest on the value given.

To calculate the amount, we use the formula below;

A = P(1 + r/n)^nt

Where; A is the amount which we want to calculate

P is the principal which is Rs 5,000

r is the interest rate per annum = 10% = 10/100 = 0.1

n is the number of times per year in which it is compounded ( since it is annually, then it is 1)

t is the number of years which is 2.5 years( kindly know that 6 months is same 1/2 year , so 6 months is same as 0.5, and thus 2 years 6 months becomes 2.5 years)

now let’s substitute all these values;

A = 5000(1 + 0.1/1)^(1*2.5)

A = 5000(1 + 0.1)^2.5

A = 5000(1.1)^2.5

A = 6,345.2935314294

This is approximately Rs 6,345.30

The second part of the question asks to calculate compound interest

Mathematically ;compound interest = Amount - principal

= 6345.3 - 5000 = Rs 1,345.30

7 0

3 years ago

4400 dollars is placed in an account with an annual interest rate of 7.5%. To the nearest tenth of a year, how long will it take

Katarina [22]

Answer:

Step-by-step explanation:

The equation for the amount of money in an account after a certain amount is deposited and compounded after t years once per year is

$A(t)=P(1+r)^t$

Our A(t) = 33800, P = 4400, r = .075 and we are looking for t. Filling in:

$33800=4400(1+.075)^t$ and

$33800=4400(1.075)^t$

Begin by dividing both sides by 4400 to get

$7.681818182=1.075^t$

The only way to move that t our from its current position as an exponent is to take the natural log of both sides and follow the rules for natural logs:

$ln(7.6181818182=ln(1.075)^t$

The power rule of natural logs says we can move that exponent down in front, giving us:

$ln(7.681818182)=t*ln(1.075)$

Divide both sides by ln(1.075) to get

$\frac{ln(7.61818182)}{ln(1.075)} =t$

Do this division on your calculator to get

t = 28.2 years

6 0

3 years ago

Read 2 more answers

16 x 0.2 in area model of mulitiplication

Reil [10]

16
0.2 = 3.2 gotta watch out for the decimals

4 0

2 years ago

Solve 6x(6x) + 11x - 35 = 0

Murljashka [212]

$36x^2 + 11x - 35=0\\\\ \frac{-b \pm \sqrt{ b^2 -4( a)(c)} }{2(a)}\\\\ \frac{-11\pm \sqrt{11^2 -4(36)(-35)} }{2(36)}\\ \\ \frac{-11\pm \sqrt{5161 } }{72}\\\\\\ x = 0.8450013919812116\\\\ \text{ } x = -1.1505569475367672$

4 0

2 years ago

Read 2 more answers