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Rashid [163]
2 years ago
9

I have 345 students and I need to fit them all into chairs. However, there are some requirements my seating plan has to keep to:

Mathematics
1 answer:
sveta [45]2 years ago
3 0

In each row, the 15 number of the student is arranged. For the given condition, the equal number of the student is to be arranged.

<h3>What is seating arrangement?</h3>

A seating arrangement is an arrangement shows that how the peoples are arranged so that the complete utilization is done.

The given data in the problem is;

The total no of student is 345 students

If the same number of the students are to be arranged for the given row, the following calculation is done;

The numbers of the student in each row is found as;

\rm  n= \frac{Total \ no \ of \ student\ }{Total\ no \of \ rows } \\\\\ n= \frac{345}{23} \\\\ n= 15 \ student

Hence, in each row, the 15 no of the student is arranged.

To learn more about the seating arrangement, refer to the link;

brainly.com/question/13492666

#SPJ1

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Rewrite this expression using a single exponent 10^2/10^5
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Answer:

10^-3

Step-by-step explanation:

so if you have 10^2/10^5, you would subtract the exponents since it is division.  2-5=-3

therefore, it would be 10^-2

Hope this helps!

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Need Help Please <br><br> what is y <br><br> 2x-4y=58?
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Answer:

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Step-by-step explanation:

2x-4y=58

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subtract 2x from each side

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Read 2 more answers
If a right triangle's hypotenuse is 17 units long, and one of its legs is 15 units long, how long is the other leg?
Vesna [10]

Answer:

8 units

Step-by-step explanation:

Hello!

So, there's a formula we can apply to right-angled triangles: Pythagorean's theorem. It states that  c = \sqrt{{a}^2 + b^{2} }, where <em>c</em> is the hypotenuse and <em>a</em> and <em>b </em>are the legs of the triangle.

So, from the problem,  if <em>c </em>= 17 and <em>a </em> = 15, then, we're solving for <em>b</em>. So we'll rewrite the theorem to solve for <em>b</em>.

{c}^2 = {a}^2+{b}^2\\{c}^2-{a}^2={b}^2\\{b} = \sqrt{{c}^2-{a}^2}

Okay, so now we have isolated the theorem for <em>b. Let's </em>plug in our values for <em>c </em>and <em>a</em>.

b = \sqrt{{17}^2-{15}^2}\\b = \sqrt{289-225}\\b = \sqrt{64}\\b = 8

So, using the theorem, we found <em>b</em> = 8. To check our work, let's plug in <em>b</em> and <em>a</em> and solve for <em>c.</em>

<em />c = \sqrt{{a}^2+{b}^2}}\\c = \sqrt{{15}^2+{8}^2}\\c = \sqrt{225+64}\\c = \sqrt{289}\\c = 17\\<em />

So, we got our hypotenuse to equal 17 units, which is correct! So, our <em>b</em> is correct too. Awesome

7 0
3 years ago
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