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3 years ago

Determine the value of each unknown variable

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

4 0

X=18 and y=10 because they are both 90degree angles therefore all you have to do is solve the equations: 5x=90 and 9y=90.

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Karen is starting a career as a professional wildlife photographer and plans to photograph Canadian Geese at one of the staging

balandron [24]

Answer:

$5000*0.816 = $4082

Step-by-step explanation:

It's a strange question, but based on the statement and the question it sounds like it's a poisson distribution:

* For 3 days she was able to get 2 good shots (<em>typical of that time of the year</em>)

* Good shots happen randomly

* Each day is independent of another

Let's call 'p' the probability that she makes a good shot per day

Let's call 'n' the number of days Karen is taking shots.

So, if in 3 days he got 2 good shots and that is typical at that time of the year, then the expected value for the number of good shots (X) is:

$E(x)=\frac{2}{3}$

For a Poisson distribution $E (x)=\lambda\\\lambda= np$

So:

$\lambda =\frac{2}{3}$

For a Poisson distribution the standard deviation is:

$\sigma = \sqrt{\lambda}\\\sigma = \sqrt{\frac{2}{3}}$

$\sigma = 0.816$ this is the standard deviation for the number of buentas taken.

So the standard deviation for income is the price of each shot per sigma

$5000*0.816 = $4082, which is the desired response.

3 0

3 years ago

Given f(x)=x^3+5x+k, and x+2 is a factor of f(x), then what is the value of k?

Marat540 [252]

3x^3+0x^2-2x+k:x-2=3x^2+6x+10
3x^2-6x^2
6x^2-2x
6x^2-12x
10x+k
10x-20
k+20
Thus k=-20

6 0

3 years ago

Read 2 more answers

Statistics Probability

andriy [413]

Answer:

Explained below.

Step-by-step explanation:

Denote the variable as follows:

M = male student

F = female student

Y = ate breakfast

N = did not ate breakfast

(a)

Compute the probability that a randomly selected student ate breakfast as follows:

$P(Y)=\frac{n(Y)}{N}\\\\=\frac{198}{330}\\\\=0.60$

(b)

Compute the probability that a randomly selected student is female and ate breakfast as follows:

$P(F\cap Y)=\frac{n(F\cap Y)}{N}\\\\=\frac{121}{330}\\\\=0.367$

(c)

Compute the probability a randomly selected student is male, given that the student ate breakfast as follows:

$P(M|Y)=\frac{n(M\cap Y)}{n(Y)}\\\\=\frac{77}{198}\\\\=0.389$

(d)

Compute the probability that a randomly selected student ate breakfast, given that the student is male as follows:

$P(Y|M)=\frac{n(Y\cap M)}{n(M)}\\\\=\frac{77}{154}\\\\=0.50$

(e)

Compute probability of the student selected "is male" or "did not eat breakfast" as follows:

$P(M\cup N)=P(M)+P(N)-P(M\cap N)\\\\=\frac{n(M)}{N}+\frac{n(N)}{N}-\frac{n(M\cap N)}{N}\\\\=\frac{n(M)-n(N)-n(M\cap N)}{N}\\\\=\frac{154+132-77}{330}\\\\=0.633$

(f)

Compute the probability of "is male and did not eat breakfast as follows:

$P(M\cap N)=\frac{n(M\cap N)}{N}\\\\=\frac{77}{330}\\\\=0.233$

4 0

3 years ago

How do you simplify (2xy2)3

pantera1 [17]

$(2xy^{2})^{3} = (2xy^{2})(2xy^{2})(2xy^{2})$
Now, we can just multiply it and obtain the result
$(2xy^{2})(2xy^{2})(2xy^{2})=(4x^{2}y^{4})(2xy^{2})=8x^{3}y^{6}$

I used law presented on this example
$2^{3}*2=2^{3}*2^{1}=2^{3+1}=2^{4}$

4 0

3 years ago

Find the slope of a line perpendicular to 3x + 5y = 15.

Zielflug [23.3K]

Answer:

B)5/3

Step-by-step explanation:

"3x + 5y = 15."

Rewrite in slope-intercept form.

The slope-intercept form is

y=mx+b

where m is the slope and b is the y-intercept.

y=mx+b

Subtract 3x from both sides of the equation.

5y=15−3x

Divide each term by "5" and simplify.

5y/5=15/5−3x/5

"5" and "5" cancel each other out

Divide 15 by 5

y=3-3x/5

Reorder 3 and −3x/5

y=-3x/5+3

Rewrite in slope-intercept form.

y=−3/5x+3

Slope:-3/5

The equation of a perpendicular line to y=−3x/5+3 must have a slope that is the negative reciprocal of the original slope.

<em>m</em>perpendicular=−1/(−3/5)

Simplify the result.

mperpendicular=5/3

hope this helps!

8 0

3 years ago