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ladessa [460]
3 years ago
10

16-2v+3 what is the answer pls help

Mathematics
1 answer:
djyliett [7]3 years ago
4 0

Answer:

the answer is 19-2v combine like terms if not that then try this....

19-2y=0

-2y=-19

Then divide by -2

y=-19/-2

=9.5

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melomori [17]

The area of the circle, to two decimal places, is A = 3.14(1.8 m)^2

Then A = 10.17 m^2.

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BRAINLIEST. MORE POINTS!!
jek_recluse [69]

Answer:  Negative slope:

Every day, I spend 100 dollars on my credit card.

Positive slope:

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7 0
3 years ago
In Triangle XYZ, A is the midpoint of XY, B is the midpoint of YZ, and C is the midpoint of XZ.
frutty [35]

The perimeter of triangle ABC is 24 units

Step-by-step explanation:

There is a fact in any triangle, the segment joining the mid points of

two sides of the triangle is:

  • Parallel to the third side
  • Its length is half the length of the third side

In Δ XYZ

∵ A is the mid point of XY

∵ B is the mid point of YZ

∴ AB = \frac{1}{2} XZ

∵ XZ = 18 units

∴ AB = \frac{1}{2} × 18 = 9 units

∵ C is the mid point of XZ

∵ B is the mid point of YZ

∴ BC = \frac{1}{2} XY

∵ AY = 7 units

∵ AY = \frac{1}{2} XY

∴ 7 = \frac{1}{2} XY

- Multiply both sides by 2

∴ 14 = XY

∴ BC = \frac{1}{2} × 14 = 7 units

∵ A is the mid point of XY

∵ C is the mid point of XZ

∴ AC = \frac{1}{2} YZ

∵ BZ = 8 units

∵ BZ = \frac{1}{2} YZ

∴ 8 = \frac{1}{2} YZ

- Multiply both sides by 2

∴ 16 = YZ

∴ AC = \frac{1}{2} × 16 = 8 units

∵ The perimeter of any triangle is the sum of the lengths of its sides

∴ Perimeter Δ ABC = AB + BC + AC

∴ Perimeter Δ ABC = 9 + 7 + 8 = 24 units

The perimeter of triangle ABC is 24 units

Learn more:

You can learn more about triangles in brainly.com/question/10677255

#LearnwithBrainly

3 0
3 years ago
3. What three numbers are the Pythagorean triple generated by using 4 for x and 1 for y. Remember to use the formulas:
Doss [256]

Given:

Consider the three number are given by:

a=x^2-y^2

b=2xy

c=x^2+y^2

To find:

The three numbers are the Pythagorean triple generated by using 4 for x and 1 for y.

Solution:

We have,

a=x^2-y^2

b=2xy

c=x^2+y^2

Substituting 4 for x and 1 for y, we get

a=4^2-1^2

a=16-1

a=15

Similarly,

b=2(4)(1)

b=8

And,

c=4^2+1^2

c=16+1

c=17

The three three numbers are the Pythagorean triple are 8,15 and 17.

Therefore, the correct option is C.

8 0
3 years ago
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