2 years ago

Prove algebraically that 0.5 recurring = 5/9

Mathematics

1 answer:

weeeeeb [17]2 years ago

5 0

Answer:

see explanation

Step-by-step explanation:

We require 2 equations with the recurring part after the decimal point.

Let x = 0.555..... → (1)

Multiply both sides by 10, then

10x = 5.555..... → (2)

Subtract (1) from (2) thus eliminating the recurring decimal

(10x - x) = (5.5555 - 0.5555 ), that is

9x = 5 ( divide both sides by 9 )

x = $\frac{5}{9}$

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On the first of three tests Kayla scored 72points. On the third test her score was 1 point more than on the second. Her average

Kitty [74]

Answer:

The answer to your question is:

first test = 72

second test = 88

third test = 89

Step-by-step explanation:

Data

First test = 72 points

Second test = x

Third test = x + 1

Average of the three test = 83

Process

(First test + Second test + Third test) / 3 = 83

( 72 + x + x +1 ) / 3 = 83

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2x = 176

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marishachu [46]

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2 years ago

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Angelina_Jolie [31]

Answer:

Step-by-step explanation:

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