Prove algebraically that 0.5 recurring = 5/9
1 answer:
Answer:
see explanation
Step-by-step explanation:
We require 2 equations with the recurring part after the decimal point.
Let x = 0.555..... → (1)
Multiply both sides by 10, then
10x = 5.555..... → (2)
Subtract (1) from (2) thus eliminating the recurring decimal
(10x - x) = (5.5555 - 0.5555 ), that is
9x = 5 ( divide both sides by 9 )
x =
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