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Yanka [14]
3 years ago
15

Please help me please please please please please help me I need your help please I’m begging you so much I need your help plz h

elp me plz plz plz help me

Mathematics
2 answers:
Step2247 [10]3 years ago
6 0

Answer:

A

Step-by-step explanation:

jeka943 years ago
5 0
A with all of them being equal you only have to divide by how many you have
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Steps for solving rational equations
Murrr4er [49]

Answer:

1. Find the common denominator.

2. Multiply everything by the common denominator.

3. Simplify.

4. Check the answer(s) to make sure there isn't an extraneous solution.

Step-by-step explanation:

Hope this helps!

5 0
2 years ago
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Please help ASAP with this one too! Thanks!
11Alexandr11 [23.1K]
Hello,

y+3=-6(x+2)
==>y=-6x-15

Answer A
3 0
3 years ago
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8/10x 1 3/5 =? would be what?
Aleonysh [2.5K]
8/10 x 1 3/5 = ?
first u need to find the mixed fraction is 8/5: 1 3/5 = 8/5
8/10 x 8/5 = 64/50 
64/50 in simplest form: 32/25 
32/25 equals to 1 7/25
so the answer is 1 and 7/25

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3 years ago
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8 0
2 years ago
What does the fundamental theorem of algebra illustrate?
UNO [17]

Answer:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

We have to find the roots of this given equation.

If a quadratic equation is of the form ax^{2}+bx +c=0

Its roots are \frac{-b+\sqrt{b^{2}-4ac } }{2a} and \frac{-b-\sqrt{b^{2}-4ac } }{2a}

Here the given equation is 2x^{2}-4x-1 = 0

a = 2

b = -4

c = -1

If the roots are x_{1} and x_{2}, then

x_{1} = \frac{-2+\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                       = \frac{4 +\sqrt{24}}{4}

                       = \frac{2+\sqrt{6} }{2}

x_{2} = \frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                        = \frac{4 +\sqrt{8}}{4}

                        = \frac{2-\sqrt{6} }{2}

These are the two roots of the equation.

6 0
2 years ago
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