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3 years ago

15

Please help me please please please please please help me I need your help please I’m begging you so much I need your help plz h

elp me plz plz plz help me

2 answers:

Step2247 [10]3 years ago

6 0

Answer:

A

Step-by-step explanation:

jeka943 years ago

5 0

A with all of them being equal you only have to divide by how many you have

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Steps for solving rational equations

Murrr4er [49]

Answer:

1. Find the common denominator.

2. Multiply everything by the common denominator.

3. Simplify.

4. Check the answer(s) to make sure there isn't an extraneous solution.

Step-by-step explanation:

Hope this helps!

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2 years ago

Read 2 more answers

Please help ASAP with this one too! Thanks!

11Alexandr11 [23.1K]

Hello,

y+3=-6(x+2)
==>y=-6x-15

Answer A

3 0

3 years ago

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8/10x 1 3/5 =? would be what?

Aleonysh [2.5K]

8/10 x 1 3/5 = ?
first u need to find the mixed fraction is 8/5: 1 3/5 = 8/5
8/10 x 8/5 = 64/50
64/50 in simplest form: 32/25
32/25 equals to 1 7/25
so the answer is 1 and 7/25

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3 years ago

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2 years ago

What does the fundamental theorem of algebra illustrate?

UNO [17]

Answer:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

We have to find the roots of this given equation.

If a quadratic equation is of the form $ax^{2}+bx +c=0$

Its roots are $\frac{-b+\sqrt{b^{2}-4ac } }{2a}$ and $\frac{-b-\sqrt{b^{2}-4ac } }{2a}$

Here the given equation is $2x^{2}-4x-1$ = 0

a = 2

b = -4

c = -1

If the roots are $x_{1} and x_{2}$ , then

$x_{1}$ = $\frac{-2+\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}$

= $\frac{4 +\sqrt{24}}{4}$

= $\frac{2+\sqrt{6} }{2}$

$x_{2}$ = $\frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}$

= $\frac{4 +\sqrt{8}}{4}$

= $\frac{2-\sqrt{6} }{2}$

These are the two roots of the equation.

6 0

2 years ago