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IrinaVladis [17]
3 years ago
12

What is the slope of the line?

Mathematics
2 answers:
Rashid [163]3 years ago
4 0

Answer:

-2/1

Step-by-step explanation:

Hope this helped!

kherson [118]3 years ago
4 0

Answer:

easy, the slope is -2/1.

Step-by-step explanation:

i found this out because you can see your y intercept is 2. you start at two then follow the line, and you go down two units (-2) and go right one unit. this equates to -2/1, which, is your slope. hope this helped!!

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vitfil [10]
The second one 

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7 0
3 years ago
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Find an equation of the line parallel to y=2x+3 and that passes through the point (5,3)
timama [110]

Answer:

y = 2x - 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x + 3 ← is in slope- intercept form

with slope m = 2

Parallel lines have equal slopes , then

y = 2x + c ← is the partial equation

To find c substitute (5, 3 ) into the partial equation

3 = 10 + c ⇒ c = 3 - 10 = - 7

y = 2x - 7 ← equation of parallel line

5 0
2 years ago
Read 2 more answers
N a recent election, Mark Benton received 780 votes for 12% of the total vote. How many people voted in the election?
Sloan [31]

Answer: Answer C

Step-by-step explanation:

12%___780 votes

100%___X= 6500 votes

(100*780)/12 = 6500

5 0
3 years ago
Simplify -4 1/4-(-9 1/2) = ? <br><br>A. -13 1/3 <br>B. -5 1/4<br>C. 13 1/3<br>D. 5 1/4​
bagirrra123 [75]

Answer:

B

Step-by-step explanation:

Hope this helps

5 0
3 years ago
A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

X=1 number of citrus trees that are infected with the citrus red mite.

n=5 random sample taken

\hat p=\frac{1}{5}=0.2 estimated proportion of citrus trees that are infected with the citrus red mite.

p true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values would be given by:

t_{\alpha/2}=-1.96, t_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.2(1-0.2)}{(\frac{0.01}{1.96})^2}=6146.56  

And rounded up we have that n=6147

5 0
3 years ago
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