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In-s [12.5K]
2 years ago
8

Which of the following is a correct description of an arithmetic sequence?

Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
8 0
Do you have answer choices ??????
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Natasha2012 [34]

Answer:

250=70x+50

Step-by-step explanation:

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2 years ago
WILL MARK BRAINLIEST !!<br> -2+a/7 = 10 <br><br> A = ? <br><br> (a/7 is a fraction)
Anvisha [2.4K]

Answer:

A=72

Step-by-step explanation:

72-2/7 = 10

72-2=70

7X10=70

6 0
3 years ago
Read 2 more answers
Let f(x) =x^2-1 and g(x) = x+3. Find f(g(x))
givi [52]

To find f(g(x)), we'll treat g(x) as if it were the x in f(x).

g(x) = x + 3

f(g(x) = (x+3)^2 - 1

5 0
3 years ago
Question 12 plz help
harkovskaia [24]

Answer:

See the attachment for the appropriate choice.

Step-by-step explanation:

Both equations are in slope-intercept form. Both have a y-intercept of -2, so only a graph where the lines cross at (x, y) = (0, -2) is a viable choice.

In both cases, the inequality requires that values of y be "less than (or equal to)" those described by the line. Hence, the shading will be below both lines.

8 0
2 years ago
Given the points C(-1,-5) and D(-7,11) find the coordinates of point E on CD such that the ratio of CE to ED is 5:3.
Anon25 [30]

Answer:

The coordinates of point E on CD are \left(-\frac{19}{4},5 \right).

Step-by-step explanation:

Let be C = (-1,-5), D = (-7,11) and \frac{CE}{ED} = \frac{5}{3}. The given ratio can be translated vectorially into this:

\overrightarrow {CE} = \frac{5}{3} \cdot \overrightarrow{ED}

And let consider that each point is a vector with respect to origin:

\vec C = (-1, -5) and \vec {D} = (-7,11)

Then,

\vec E -\vec C = \frac{5}{3}\cdot (\vec D -\vec E)

\vec E +\frac{5}{3}\cdot \vec E = \frac{5}{3}\cdot \vec D + \vec C

\frac{8}{3}\cdot \vec E = \frac{5}{3}\cdot \vec D + \vec C

\vec E = \frac{5}{8}\cdot \vec D + \frac{3}{8}\cdot \vec C

\vec E = \frac{5}{8}\cdot (-7,11)+\frac{3}{8}\cdot (-1,-5)

\vec E = \left(-\frac{35}{8},\frac{55}{8}  \right)+\left(-\frac{3}{8},-\frac{15}{8}  \right)

\vec E = \left(-\frac{35}{8}-\frac{3}{8},\frac{55}{8}-\frac{15}{8}    \right)

\vec{E} = \left(-\frac{19}{4}, 5\right)

The coordinates of point E on CD are \left(-\frac{19}{4},5 \right).

6 0
3 years ago
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