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3 years ago

PLEASE ANSWER! DONE IN 30 MINUTES. THE CORRECT ANSWER WILL GET BRANLIST AND 50 EXTRA POINTS!

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

8 0

17) It may help to graph it if you can, it's hard to do online on here

18) The formula for the surface area of a prism is (2 × Base Area) + (Base perimeter × height) so

(2 x 5 cm) + (12 x 2)

(10 cm) + (24 cm)

34 cm

19) D 1 rectangle and 2 circles, a "net" is what it looks like 2D

20) Unsure, sorry!

I did as much as I could haha, have a good day and good luck!

marta [7]3 years ago

7 0

Answer:

Step-by-step explanation:

give brainly

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HELP WITH ONE MATH QUESTION!!! 20 POINTS AND WILL MARK BRAINLIEST

Jobisdone [24]

Answer:

6/h = 10/40

Step-by-step explanation:

6/h = 10/40

8 0

3 years ago

1. (5pts) Find the derivatives of the function using the definition of derivative.

andreyandreev [35.5K]

2.8.1

$f(x) = \dfrac4{\sqrt{3-x}}$

By definition of the derivative,

$f'(x) = \displaystyle \lim_{h\to0} \frac{f(x+h)-f(x)}{h}$

We have

$f(x+h) = \dfrac4{\sqrt{3-(x+h)}}$

and

$f(x+h)-f(x) = \dfrac4{\sqrt{3-(x+h)}} - \dfrac4{\sqrt{3-x}}$

Combine these fractions into one with a common denominator:

$f(x+h)-f(x) = \dfrac{4\sqrt{3-x} - 4\sqrt{3-(x+h)}}{\sqrt{3-x}\sqrt{3-(x+h)}}$

Rationalize the numerator by multiplying uniformly by the conjugate of the numerator, and simplify the result:

$f(x+h) - f(x) = \dfrac{\left(4\sqrt{3-x} - 4\sqrt{3-(x+h)}\right)\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ f(x+h) - f(x) = \dfrac{\left(4\sqrt{3-x}\right)^2 - \left(4\sqrt{3-(x+h)}\right)^2}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ f(x+h) - f(x) = \dfrac{16(3-x) - 16(3-(x+h))}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ f(x+h) - f(x) = \dfrac{16h}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)}$

Now divide this by h and take the limit as h approaches 0 :

$\dfrac{f(x+h)-f(x)}h = \dfrac{16}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \dfrac{16}{\sqrt{3-x}\sqrt{3-x}\left(4\sqrt{3-x} + 4\sqrt{3-x}\right)} \\\\ \implies f'(x) = \dfrac{16}{4\left(\sqrt{3-x}\right)^3} = \boxed{\dfrac4{(3-x)^{3/2}}}$

3.1.1.

$f(x) = 4x^5 - \dfrac1{4x^2} + \sqrt[3]{x} - \pi^2 + 10e^3$

Differentiate one term at a time:

• power rule

$\left(4x^5\right)' = 4\left(x^5\right)' = 4\cdot5x^4 = 20x^4$

$\left(\dfrac1{4x^2}\right)' = \dfrac14\left(x^{-2}\right)' = \dfrac14\cdot-2x^{-3} = -\dfrac1{2x^3}$

$\left(\sqrt[3]{x}\right)' = \left(x^{1/3}\right)' = \dfrac13 x^{-2/3} = \dfrac1{3x^{2/3}}$

The last two terms are constant, so their derivatives are both zero.

So you end up with

$f'(x) = \boxed{20x^4 + \dfrac1{2x^3} + \dfrac1{3x^{2/3}}}$

8 0

2 years ago

Suppose a population has a mean of 400 and a standard deviation of 24. if a random sample of size 144 is drawn from the populati

Drupady [299]

Find the critical value or test statistic.
$z = \frac{m - \mu}{\sigma/\sqrt{n}} = \frac{404.5 - 400}{24/\sqrt{144}} = \frac{4.5}{2} = 2.25$

Find P(z > 2.25) using a normal distribution table

P(z > 2.25) = 0.0122

6 0

2 years ago

Please help! I will give brainliest and 5 stars!

Ierofanga [76]

Answer:

(A.) x = y - 4

Step-by-step explanation:

All you need to do is subtract the 4 from both sides, giving you the final equation as x = y - 4.

7 0

3 years ago

Rylee saved $9 on a $60 pair of shoes. What percent did she save?

Ilia_Sergeevich [38]

Answer:

15%

Step-by-step explanation:

9/60=3/20=15%

8 0

2 years ago