I think its EB.
Hope this helps!
Answer:
Hamburger buns: 7
Hot dog buns- 4
what does it mean by system?
find the mean, median, and interquartile range for the data set below. 5,8,9,11,13,15,16,17,17,18,22,23
Alekssandra [29.7K]
Answer:
Mean: 14.5
Median: 15.5
IQR = 7.5
Step-by-step explanation:
For mean:
Mean= (∑x)/n
=(5+8+9+11+13+15+16+17+17+18+22+23)/12
= 174/12
=14.5
Median:
As the data is already sorted and the number of items are odd, average of two middle values will be the median of the data.
5,8,9,11,13,15,16,17,17,18,22,23
Median=(15+16)/2
=31/2
=15.5
IQR:
For IQR, the data has to be divided in two parts, lower and upper, then we have to find the median of both parts separately. The difference of medians of both parts is called the Interquartile range.
So for lower part,
5,8,9,11,13,15
Median for lower part= (9+11)/2
= 20/2
=10
For upper part:
16,17,17,18,22,23
Median for lower part= (17+18)/2
= 35/2
=17.5
IQR=17.5-10
=7.5
Answer:
- equivalent rate: 7.186%
- compounded 16 times
Step-by-step explanation:
The equivalent interest rate is the rate that would have to be applied so it would earn the same amount in 1 year. It is computed from ...
requiv = (1 +r/n)^n -1
requiv = (1 +0.07/4)^4 -1 ≈ 7.186%
__
"Compounded quarterly" means interest is compounded 4 times per year. In 4 years, it will be compounded 4·4 = 16 times.
__
The balance in the account after 4 years is ...
$600·(1 +.07/4)^(4·4) ≈ $791.96
Answer:
a) -2x^2 + 164x
b) 3362 feet
c) (82 , -328)
d) yes
Step-by-step explanation:
y = -2x^2 + 160x
Slope = 4 feet downward for every 1 horizontal foot.
a) h(x) = -2x^2 + 160x - (-4x)
= -2x^2 + 160x + 4x
= -2x^2 + 164x
b) The highest point occurs at the vertex of the parabolic equation. x is the same as the number of the axis of symmetry.
x = -b/2a
From the equation, a = -2 , b= 164
x = -164/ 2(-2)
x = -164/-4
x = 41
Put x = 41 into the value of h(x)
h(x) = -2x^2 + 164x
= -2(41^2) + 164(41)
= -2(1681) + 6724
= -3362 + 6724
= 3362 feet.
The maximum height occurs at 41 feet out from the top of the sloping ground at a height of 3362ft about the top edge of the cliff.
c) h(x) = -2x^2 + 164x
2x^2 - 164x + h = 0 when 0 ≤ x ≤ 41
Solve the equation using the formula (-b+/-√b^2 - 4ac) / 2a
a = 2, b= -164 , c = h
= [-(-164) +/- √(-164)^2 - 4(2)(h) ] / 2(2)
= (164 +/- √26896 - 8h)/ 4
This gives the value of -328 ≤ h ≤ 3362 is used because the rocket hits the sloping ground of (82 , -328)
d) the function still works when it is going down
