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posledela
3 years ago
11

Solve the equation 5x + 2(2x -23) = -154

Mathematics
2 answers:
sammy [17]3 years ago
8 0

Answer:

x = -12

Step-by-step explanation:

5x + 2(2x - 23) = -154

Distribute;

5x + 4x - 46 = -154

Collect like terms

9x - 46 = -154

Add 46 to both sides;

9x = -108

Divide both sides by 9

x = -12

Anon25 [30]3 years ago
4 0

\boxed{\large{\bold{\blue{ANSWER~:) }}}}

  • 5x+2(2x-23)=-154

  • 5x+4x-46=-154

  • 9x-46=-154

  • 9x=-154+46

  • 9x=-108

  • x=\sf{\dfrac{-108}{9}  }

  • x=-12
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Andell is 9 years older than Arnez. arnez is 3 years younger than Marianne. the sum of their ages is 24. what is the age of each
Harman [31]

Answer:

Arnez is 4. Andell is 13. Marianne is 7.

Step-by-step explanation:

Let x represent Arnez's age. If we write out an equation, we end up with this:

24 = (9 + x) + (x + 3) + x

24 = 9 + x + x + 3 + x

24 = (x + x + x) + (9 + 3)

24 = 3x + 12

24 - 12 = 3x + 12 - 12

12 / 3 = 3x / 3

4 = x

5 0
3 years ago
The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

Option 5 is incorrect

6)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5

Since 1.5 is between 1 and 2, option 6 is correct

5 0
3 years ago
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butalik [34]

Answer:

B, E, D, and C

Step-by-step explanation:

5 0
2 years ago
Please help thx a bunch
kirza4 [7]
A.
2/3A=-24
time both sides by 3/2
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A=-36

B.
20=-B/0.2
times both sides by 0.2
4=-B
times -1
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distance between 2 points x and y is |x-y|

so
distance between A and B is distance between -4 and -72 or
|-72-(-4)|=|-72+4|=|-68|=68
the distance is 68
4 0
3 years ago
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Georgia [21]

To fond the area of a trapezoid, add the top and bottom together, divide that by 2, than multiply by the height.

Area = (8+12)/2 = 20/2 = 10

10 x 9 = 90 square centimeters.

5 0
3 years ago
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