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3 years ago

Choose the equation for the graph below

Mathematics

1 answer:

Alex Ar [27]3 years ago

8 0

The answer to your question is “D”

Btw you can use DESMOS for future questions like this

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How many cubic centimeters of water can this paper cone cup hold?

blagie [28]

48π cm^3

Step-by-step explanation:

The formula for the volume of a cone is...

$V=\frac{1}{3}\pi r^2h$

We can plug everything we know from the photo into the equation, but note that the picture gives us the diameter, which is 8, instead of the radius. The radius is half of the diameter, so the radius will be 4. Also we will be leaving pi as it is, instead of changing it to 3.14.

$V=\frac{1}{3}*(\pi *4*4*9)$

$V=\frac{1}{3}*(144\pi )$

V = 48π

The paper cone can hold 48π cubic centimeters of water.

3 0

3 years ago

Read 2 more answers

the length of a rectangle is 8cm more than the width and its area is 172cm2 .find the width of the rectabgle

nikdorinn [45]

$l-the\ length\\l+8-the\ width\\A=172\ cm^2\\\\A=lengtf\cdot width\\\\subtitute\\\\l(l+8)=172\\\\l^2+8l=172\ \ \ |subtract\ 172\ from\ both\ sides\\\\l^2+8l-172=0\\a=1;\ b=8;\ c=-172\\\\\Delta=b^2-4ac\\\\\Delta=8^2-4\cdot1\cdot(-172)=64+688=752 > 0\\\\l_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ l_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{752}=\sqrt{16\cdot47}=4\sqrt{47}\\\\l_1=\dfrac{-8-4\sqrt{47}}{2\cdot1}=-4-2\sqrt{47} < 0\\\\l_2=\dfrac{-8+4\sqrt{47}}{2\cdot1}=-4+2\sqrt{47} > 0\\\\The\ width:l+8=-4+2\sqrt{47}+8=4+2\sqrt{47}\\\\Answer:\boxed{length=(2\sqrt{47}-4)cm;\ width=(4+2\sqrt{47})cm}$
$length\approx9.71cm;\ width\approx17.71cm$

4 0

3 years ago

Solve the following system of equations. 2x + y = 3 x = 2y - 1

Shalnov [3]

2(2y-1)+y=3
y=1
x=2 x1 - 1
x=1

7 0

3 years ago

Read 2 more answers

The owner of Darkest Tans Unlimited in a local mall is forecasting the demand for November the one new tanning booth based on th

lorasvet [3.4K]

Answer:

The forecast for November is 235 if August's forecast was 145.

Step-by-step explanation:

The formula for calculating forecast using exponential smoothing is:

$F_{t} = F_{t-1} + \alpha (A_{t-1} - F_{t-1} )$

Where Ft = New month forecast

Ft-1 = Previous month forecast

At-1 = Previous month actual value

α = smoothing constant

We are given F₈ = 145 (forecast for August), A₈ = 200 (Actual Value for August), α = 2, and we need to compute the forecast for November. So, We will first calculate the forecast for September then October and then November, step-by-step.

So, forecast for September is:

F₉ = F₈ + α (A₈ - F₈)

= 145 + 2*(200-145)

= 145 + 2*55

F₉ = 255

Then, forecast for October is:

F₁₀ = F₉ + α (A₉ - F₉)

= 255 + 2*(220-255)

= 255 + 2*(-35)

F₁₀ = 185

The forecast for November is:

F₁₁ = F₁₀ + α (A₁₀ - F₁₀)

= 185 + 2*(210 - 185)

F₁₁ = 235

8 0

3 years ago

Answer the two questions below

STALIN [3.7K]

Answer:

3: No

4: 25

Step-by-step explanation:

3: It won't because not everyone is the same height and there will be variation in the mean height.

4: A larger sample size will give a more accurate representation of the population, where as a sample size of 5 is much more likely to have a higher percentage of outliers, and each outlier matters much more in finding the mean. In a sample size of 25, each outlier matters much less.

8 0

2 years ago