The triple integral that is bounded by a paraboloid x = 4y2 4z2 given as
Parabloid, x = 4y^2 + 4z^2
plane x = 4
x = 4y^2 + 4z^2
x = 4
4 = 4y^2 + 4z^2
4 = 4 (y^2 + z^2 )
1 = y^2 + z^2
from polar coordinates
y = r cos θ
z = r sin θ
r^2 = y^2 + z^2
<h3>limts of the integral</h3>
0 ≤ θ ≤ 2π
4r^2 ≤ x ≤ 4
0 ≤ r ≤ 1
where
a = 4
b = 4r^2
c = 2r
d = 0
The first integral using limits c and d gives:
The second integral using limits a and b
The third integral using limits 1 and 0 gives:
Read more on Triple integral here: brainly.com/question/27171802
When a problem comes along, you must whip it.
Answer: 59.91%.
Step-by-step explanation:
- We know that the fraction of the variability in data values accounted by a model is given by , where r is the coefficient of correlation.
We are given , that the correlation between a car’s engine size and its fuel economy (in mpg) is r = - 0.774.
Then, the fraction of the variability in fuel economy is accounted for by the engine size would be
[Multiply 100 to convert a decimal into percent]
Hence, the fraction of the variability in fuel economy is accounted for by the engine size is 59.91%.
None of the options are correct.
The answer is 16 metric units by the quarter mile
Answer:
1485120
Step-by-step explanation:
Since the order of arrangement does not matter, we use combination :
Recall :
nCr = n! ÷ (n-r)!r!
For administrator : 1 out of 5 :
5C1 = 5! ÷ (5-1)!1!
For faculty members : 3 out of 14 :
14C3 = 14! ÷ (14 - 3)!3!
For students : 3 out of 18 :
18C3 = 18! ÷ (18 - 3)!3!
5C1 * 14C3 * 18C3 = 1485120